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The mean of given data is 26. C.I. 0 - 20 20 - 40 40 - 60 f 20 x 10 Statement (1): x = 26. Statement (2): 26=10×20+30×𝑥+50×10/30+𝑥

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Question

The mean of given data is 26.

C.I. 0 - 20 20 - 40 40 - 60
f 20 x 10

Statement (1): x = 26.

Statement (2): \[26=\frac{10 \times 20+30 \times x+50 \times 10}{30+x}\]

Options

  • Both the statements are true.

  • Both the statements are false.

  • Statement 1 is true, and statement 2 is false.

  • Statement 1 is false, and statement 2 is true.

MCQ
Assertion and Reasoning
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Solution

Statement 1 is false, and statement 2 is true.

Explanation:

Given:

C.I. f x(Midpoint) = (Lower limit + upper limit)/2
0-20 20 10
20-40 x 30
40-60 10 50

By formula; \[\text{Mean} = \frac{\Sigma f.x}{\Sigma f}\]

Substituting the values, we get

\[\Rightarrow 26 = \frac{20 \times 10 + x \times 30 + 10 \times 50}{x + 30}\]

So, statement 2 is true.

\[\Rightarrow 26 = \frac{200 + 30x + 500}{30 + x}\]

\[\Rightarrow 26(30 + x) = 200 + 30x + 500\]

\[\Rightarrow 780 + 26x = 700 + 30x\]

\[\Rightarrow 30x - 26x = 780 - 700\]

\[\Rightarrow 4x = 80\]

\[\Rightarrow x = \frac{80}{4}\]

\[\Rightarrow x = 20\]

∴ Statement 1 is false, and statement 2 is true.

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Chapter 24: Measure of Central Tendency (Mean, Median, Quartiles and Mode) - TEST YOURSELF [Page 388]

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Selina Concise Mathematics [English] Class 10 ICSE
Chapter 24 Measure of Central Tendency (Mean, Median, Quartiles and Mode)
TEST YOURSELF | Q 1. (j) | Page 388
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