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The mean of the given frequency distribution is: x 30 20 f 15 5

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Question

The mean of the given frequency distribution is:

x 30 20
f 15 5

Options

  • \[\frac{30}{15}+\frac{20}{5}\]

  • \[\frac{30}{15}-\frac{20}{5}\]

  • \[\frac{550}{20}=27.5\]

  • \[\frac{50}{20}=2 \cdot 5\]

MCQ
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Solution

\[{\boldsymbol{\frac{550}{20}=27.5}}\]

Explanation:

x f fx
30 15 450
20 5 100
Total Σf = 20 Σfx = 550

By formula, \[\text{Mean} = \frac{\Sigma fx}{\Sigma f} = \frac{550}{20} = 27.5\]

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Chapter 24: Measure of Central Tendency (Mean, Median, Quartiles and Mode) - EXERCISE 24 (A) [Page 368]

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Selina Concise Mathematics [English] Class 10 ICSE
Chapter 24 Measure of Central Tendency (Mean, Median, Quartiles and Mode)
EXERCISE 24 (A) | Q 1. (e) | Page 368
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