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Chapters
1: Goods and Services Tax (G.S.T.)
2: Banking
3: Shares and Dividends
UNIT 2: ALGEBRA
4: Linear Inequations
5: Quadratic Equation
Chapter 6: Problems on Quadratic Equations
▶ 7: Ratio and Proportion
Chapter 8: Remainder Theorem and Factor Theorem
9: Matrices
Chapter 10: Arithmetic Progression
Chapter 11: Geometric Progression
12: Reflection
Chapter 13: Section and Mid-point Formulae
Chapter 14: Equation of a Straight Line
UNIT 3: GEOMETRY
Chapter 15: Similarity (As a Size Transformation)
Chapter 16: Similarity of Triangles
17: Loci
Chapter 18: Angle and Cyclic Properties of a Circle
Chapter 19: Tangent Properties of Circles
20: Constructions
UNIT 4: MENSURATION
Chapter 21: Volume and Surface Area of Solids (Cylinder, Cone and Sphere)
UNIT 5: TRIGONOMETRY
Chapter 22: Trigonometrical Identities
Chapter 23: Heights and Distances
UNIT 6: STATISTICS
Chapter 24: Graphical Representation of Statistical Data
Chapter 25: Measures of Central Tendency (Mean)
Chapter 26: Median, Quartiles and Mode
UNIT 7: PROBABILITY
Chapter 27: Probability
Chapter *: Competency-Focused Questions Released by CISCE
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Solutions for Chapter 7: Ratio and Proportion
Below listed, you can find solutions for Chapter 7 of CISCE R.S. Aggarwal for Mathematics [English] Class 10 ICSE.
R.S. Aggarwal solutions for Mathematics [English] Class 10 ICSE 7 Ratio and Proportion Exercise 1
Which is greater 4: 5 or 19: 25.
Arrange 5: 6, 8: 9, 13: 18 and 7: 12 in ascending order of magnitude.
Find:
The sub-triplicate ratio of the sub-duplicate ratio of 729x18: 64y6.
Find:
The sub-duplicate ratio of the sub-triplicate ratio of 4096x6: 729y12.
If 3x – 2y – 7z = 0 and 2x + 3y – 5z = 0 find x : y : z.
If b is the mean proportional between a and c, prove that `(a^2 - b^2 + c^2)/(a^-2 -b^-2 + c^-2)` = b4.
Two numbers are in the ratio of 3: 5. If 8 is added to each number, the ratio becomes 2 : 3. Find the numbers.
If x : y = 2 : 3, find the value of (3x + 2y) : (2x + 5y).
Divide Rs. 720 between Sunil, Sbhil and Akhil. So that Sunil gets 4/5 of Sohil’s and Akhil’s share together and Sohil gets 2/3 of Akhil’s share.
The ratio between two numbers is 3: 4. If their L.C.M., is 180. Find the numbers.
If (x - 9) : (3x + 6) is the duplicate ratio of 4 : 9, find the value of x.
Find the compound ratio of the following:
If A : B = 4 : 5, B : C = 6 : 7 and C : D = 14 : 15. Find A : D.
Find the compound ratio of the following:
If P : Q = 6 : 7, Q : R = 8 : 9 find P : Q : R.
Find: The duplicate ratio of 7: 9
Find: The triplicate ratio of 3: 7
Find: The sub-duplicate ratio of 256: 625
Find: The sub-triplicate ratio of 216: 343
Find: The reciprocal ratio of 8: 15.
If `(x^2 + y^2)/(x^2 - y^2) = 17/8`, then find the value of:
- x : y
- `(x^3 + y^3)/(x^3 - y^3)`
What number must be added to each of the numbers 6, 15, 20 and 43 to make them proportional?
What least number must be added to each of the numbers 5, 11, 19 and 37, so that they are in proportion?
What quantity must be added to each term of the ratio a + b: a - b to make it equal to (a + b)2 : (a - b)2 ?
The work done by (x – 3) men in (2x + 1) days and the work done by (2x + 1) men in (x + 4) days are in the ratio of 3: 10. Find the value of x.
Find the third proportional to:
x - y, x2 - y2
Find the third proportional to:
`a/b + b/c, sqrt(a^2 + b^2)`.
Find the fourth proportional to:
2xy, x2, y2
Find the fourth proportional to:
x3 - y2, x4 + x2y2 + y4, x - y.
Find the two numbers such that their mean proprtional is 24 and the third proportinal is 1,536.
Using componendo and idendo, find the value of x
`(sqrt(3x + 4) + sqrt(3x - 5))/(sqrt(3x + 4) - sqrt(3x - 5)` = 9
Solve for x: `(3x^2 + 5x + 18)/(5x^2 + 6x + 12) = (3x + 5)/(5x - 6)`.
Using the properties of proportion, solve for x, given. `(x^4 + 1)/(2x^2) = (17)/(8)`.
Given that `(a^3 + 3ab^2)/(b^2 + 3a^2b) = (63)/(62)`.
Using Componendo and Dividendo find a : b.
If `(3x + 5y)/(3x - 5y) = (7)/(3)`, find x : y.
Solve for x : `(1 - px)/(1 + px) = sqrt((1 + qx)/(1 - qx)`
Find the value of
`(x + sqrt(3))/(x - sqrt(3)) + (x + sqrt(2))/(x - sqrt(2)), if x = (2sqrt(6))/(sqrt(3) + sqrt(2)`.
R.S. Aggarwal solutions for Mathematics [English] Class 10 ICSE 7 Ratio and Proportion Exercise 2
If (a – x) : (b – x) be the duplicate ratio of a: b show that:
`(1)/x = (1)/a + (1)/b.`
If a: b with a ≠ b is the duplicate ratio of a + c: b + c, show that c2 = ab.
If a : b = 5 : 3, show that (5a + 8b) : (6a – 7b) = 49 : 9.
If `a/b = c/d = e/f`, Prove that each of these ratios is equal to `(a + c + e)/(b + d + f)`.
If `a/(b + c) = b/(c + a) = c/(a + b)`, show that each ratio is equal to `(1)/(2) or -1`.
If `(8a - 5b)/(8c - 5d) = (8a + 5b)/(8c + 5d)`, prove that `a/b = c/d.`
If x and y be unequal and x: y is the duplicate ratio of (x + z) and (y + z) prove that z is mean proportional between x and y.
Show, that a, b, c, d are in proportion if:
(6a + 7b) : (6c + 7d) : : (6a - 7b) : (6c - 7d)
If (a + b + c + d) (a – b – c + d) = (a + b – c – d) (a – b + c – d), prove that a : b = c : d.
If ax = by = cz, prove that
`x^2/(yz) + y^2/(zx) + z^2/(xy) = (bc)/a^2 + (ca)/b^2 + (ab)/c^2`.
If `(by + cz )/(b^2 + c^2) = (cz + ax)/(c^2 + a^2) = (ax + by)/(a^2 + b^2)` then show that each ratio is equal to `x/a = y/b = z/c`.
If y = `(sqrt(a + 3b) + sqrt(a - 3b))/(sqrt(a + 3b) - sqrt(a - 3b))`, show that 3by2 - 2ay + 3b = 0.
If a, b, c are in continued proportion, prove that a : c = (a2 + b2) : (b2 + c2).
If y = `((p + 1)^(1/3) + (p - 1)^(1/3))/((p + 1)^(1/3) - (p - 1)^(1/3)` find that y3 - 3py2 + 3y - p = 0.
If `x/(b + c - a) = y/(c + a - b) = z/(a + b - c)` then show that (b - c)x + (c - a)y + (a - b) z = 0.
If p + r = 2q and `(1)/q + (1)/s = (2)/r`, then prove that p : q = r : s.
if x = `(sqrt(a + 1) + sqrt(a-1))/(sqrt(a + 1) - sqrt(a - 1))` using properties of proportion show that `x^2 - 2ax + 1 = 0`
Given : x = `(sqrt(a^2 + b^2)+sqrt(a^2 - b^2))/(sqrt(a^2 + b^2)-sqrt(a^2 - b^2))`
Use componendo and dividendo to prove that `b^2 = (2a^2x)/(x^2 + 1)`.
If `a/b = c/d,` show that (9a + 13b) (9c - 13d) = (9c + 13b) (9a - 13d).
If `p/q = r/s`, prove that `(2p + 3q)/(2p - 3q) = (2r + 3s)/(2r - 3s)`.
If a, b, c, d are in continued proportion, prove that (b − c)2 + (c − a)2 + (d − b)2 = (d − a)2.
If q is the mean proportional between p and r, prove that
`p^2 - q^2 + r^2 = q^4[(1)/p^2 - (1)/q^2 + (1)/r^2]`.
If `a/b = c/d` Show that a + b : c + d = `sqrt(a^2 + b^2) : sqrt(c^2 + d^2)`.
If a : b = c : d, show that (a - c) b2 : (b - d) cd = (a2 - b2 - ab) : (c2 - d2 - cd).
If `a/b = c/d = e/f`, prove that `(ab + cd + ef)^2 = (a^2 + c^2 + e^2) (b^2 + d^2 + f^2)`.
If `a/b = c/d = r/f`, prove that `((a^2b^2 + c^2d^2 + e^2f^2)/(ab^3 + cd^3 + ef^3))^(3/2) = sqrt((ace)/(bdf)`
If a, b, c, d are in continued proportion, prove that:
`sqrt(ab) - sqrt(bc) + sqrt(cd) = sqrt((a - b + c) (b - c + d)`
If a, b, c, d are in continued proportion, prove that:
(a2 + b2 + c2) (b2 + c2 + d2) = (ab + bc + cd)2.
If `x/a = y/b = z/c`, show that `x^3/a^3 - y^3/b^3 = z^3/c^3 = (xyz)/(zbc).`
If `x/a = y/b = z/c`, prove that `x^3/a^2 + y^2/b^2 + z^3/c^2 = ((x + y + z)^3)/((a + b ++ c)^2)`.
If `a = (b + c)/(2), c = (a + b)/(2)` and b is mean proportional between a and c, prove that `(1)/a + (1)/c = (1)/b`.
if `(3a + 4b)/(3c + 4d) = (3a - 4b)/(3c - 4d)` Prove that `a/b = c/d`.
If a : b = c : d, show that (2a - 7b) (2c + 7d) = (2c - 7d) (2a + 7b).
If `(3x + 4y)/(3u + 4v) = (3x - 4y)/(3u - 4v)`, then show that `x/y = u/v`.
R.S. Aggarwal solutions for Mathematics [English] Class 10 ICSE 7 Ratio and Proportion Exercise 3
The hypotenuse of a right angled triangle is 3`sqrt(5)`. If the smaller side is tripled and the larger side is doubled, the new hypotenuse will be 15 cm. Find the length of each side.
Solutions for 7: Ratio and Proportion
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R.S. Aggarwal solutions for Mathematics [English] Class 10 ICSE chapter 7 - Ratio and Proportion
Shaalaa.com has the CISCE Mathematics Mathematics [English] Class 10 ICSE CISCE solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. R.S. Aggarwal solutions for Mathematics Mathematics [English] Class 10 ICSE CISCE 7 (Ratio and Proportion) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.
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Concepts covered in Mathematics [English] Class 10 ICSE chapter 7 Ratio and Proportion are Ratio, Proportion, Direct Applications of Ratio and Proportion, Ratio in Lowest Terms, All About Ratios: Dividing, Comparing, and Modifying Quantities, Commensurable and Incommensurable Quantities, Composition of Ratios, Concept of Continued Proportion, Properties of Proportion, Ratio, Proportion, Direct Applications of Ratio and Proportion, Ratio in Lowest Terms, All About Ratios: Dividing, Comparing, and Modifying Quantities, Commensurable and Incommensurable Quantities, Composition of Ratios, Concept of Continued Proportion, Properties of Proportion.
Using R.S. Aggarwal Mathematics [English] Class 10 ICSE solutions Ratio and Proportion exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in R.S. Aggarwal Solutions are essential questions that can be asked in the final exam. Maximum CISCE Mathematics [English] Class 10 ICSE students prefer R.S. Aggarwal Textbook Solutions to score more in exams.
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