Advertisements
Advertisements
Question
What least number must be added to each of the numbers 5, 11, 19 and 37, so that they are in proportion?
Advertisements
Solution
Let x be the number added to 5, 11, 19, 37.
`(5 + x)/(11 + x) = (19 + x)/(37 + x)`
App. comp. and divi.
`(5 + x + 11 + x)/(5 + x - 11 - x) = (19 + x + 37 + x )/(19 + x - 37 - x)`
`(16 + 2x)/(-6) = (56 + 2x)/(-18)`
3(16 + 2x) = 56 + 2x
6x - 2x = 56 - 48
4x = 8
x = 2.
APPEARS IN
RELATED QUESTIONS
Find the fourth proportion to the following :
(x2 - y2),(x3 + y3)anc(x3 - xy2 + x2y- y3)
Given four quantities p, q, r and s are in proportion, show that
q2(p - r) : rs (q - s) =(p2- q2- pq): ( r2-s2-rs).
If ( a+c) : b = 5 : 1 and (bc + cd) : bd = 5 : 1, then prove that a : b = c : d
What number must be added to each of the numbers 16, 26 and 40 so that the resulting numbers may be in continued proportion?
An electric pole casts a shadow of length 20 m at a time when a tree 6 m high casts a shadow of length 8 m. Find the height of the pole.
If 48 boxes contain 6000 pens, how many such boxes will be needed for 1875 pens?
If a, b, c, d, e are in continued proportion, prove that: a : e = a4 : b4.
Are 30, 40, 45, and 60 in proportion?
A gets double of what B gets and B gets double of what C gets. Find A : B and B : C and verify whether the result is in proportion or not
Are the following statements true?
40 persons : 200 persons = ₹ 15 : ₹ 75
