Advertisements
Advertisements
Question
6 is the mean proportion between two numbers x and y and 48 is the third proportional of x and y. Find the numbers.
Advertisements
Solution
6 is the mean proportion between two numbers x and y,
`i.e 6 = sqrt(xy)`
So, 36 = xy ...(1)
It is given that 48 is the third proportional to x and y
So, y2 = 48x … (2)
From (1) and (2), we get
`y^2 = 48 (36/y) => y^3 = 1728`
Hence, y = 12
`:. x = 36/y = 36/12 = 3`
Thus, the required numbers are 3 and 12.
APPEARS IN
RELATED QUESTIONS
Check whether the following numbers are in continued proportion.
3, 5, 8
Find the third proportion to the following :
16x2 and 24x
Using the properties of proportion, solve for x, given. `(x^4 + 1)/(2x^2) = (17)/(8)`.
Find the value of x in the following proportions : 10 : 35 = x : 42
What number should be subtracted from each of the numbers 23, 30, 57 and 78 so that the remainders are in proportion ?
Show that the following numbers are in continued proportion:
16, 84, 441
24 workers can build a wall in 15 days. How many days will 9 workers take to build a similar wall?
Two numbers are in the ratio 5 : 7 and the sum of these numbers is 252. The larger of these numbers is
The shadow of a 3 m long stick is 4 m long. At the same time of the day, if the shadow of a flagstaff is 24 m long, how tall is the flagstaff?
The quarterly school fee in Kendriya Vidyalaya for Class VI is Rs. 540. What will be the fee for seven months?
