Advertisements
Advertisements
प्रश्न
6 is the mean proportion between two numbers x and y and 48 is the third proportional of x and y. Find the numbers.
Advertisements
उत्तर
6 is the mean proportion between two numbers x and y,
`i.e 6 = sqrt(xy)`
So, 36 = xy ...(1)
It is given that 48 is the third proportional to x and y
So, y2 = 48x … (2)
From (1) and (2), we get
`y^2 = 48 (36/y) => y^3 = 1728`
Hence, y = 12
`:. x = 36/y = 36/12 = 3`
Thus, the required numbers are 3 and 12.
APPEARS IN
संबंधित प्रश्न
If p : q = r : s; then show that: mp + nq : q = mr + ns : s.
Find the mean proportion of: 8.1 and 2.5
If 9 kg of rice costs Rs 327.60, what will be the cost of 50 kg of rice?
35 inland letters cost Rs 87.50. How many such letters can we buy for 315?
If Rs 760 is divided between A and B in the ratio 8 : 11, then B's share is
If `a/c = c/d = c/f` prove that : `(a^2)/(b^2) + (c^2)/(d^2) + (e^2)/(f^2) = "ac"/"bd" + "ce"/"df" + "ae"/"df"`
If a, b, c and d are in proportion, prove that: (5a + 7b) (2c – 3d) = (5c + 7d) (2a – 3b).
If a, b, c and d are in proportion, prove that: `(a^2 + ab)/(c^2 + cd) = (b^2 - 2ab)/(d^2 - 2cd)`
The length and breadth of a school ground are 150 m and 90 m respectively, while the length and breadth of a mela ground are 210 m and 126 m, respectively. Are these measurements in proportion?
The quarterly school fee in Kendriya Vidyalaya for Class VI is Rs. 540. What will be the fee for seven months?
