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Arrange 5: 6, 8: 9, 13: 18 and 7: 12 in Ascending Order of Magnitude.

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Question

Arrange 5: 6, 8: 9, 13: 18 and 7: 12 in ascending order of magnitude.

Sum
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Solution

The given ratios are 5: 6, 8: 9, 13: 18 and 7: 12.
Now L.C.M., of 6, 9, 18 and 12 = 36
Now `(5)/(6) = (5 xx 6)/(6 xx 6) = (30)/(36)`

`(8)/(9) = (8 xx 4)/(9 xx 4) = (32)/(36)`

`(13)/(18) = (13 xx 2)/(18 xx 2) = (26)/(36)`

Also `(7)/(12) = (7 xx 3)/(12 xx 3) = (21)/(36)`

Here `(21)/(36) < (26)/(36) < (30)/(36) < (32)/(36)`

Hence `(7)/(12) < (13)/(18) < (5)/(6) < (8)/(9)`
i.e., Ascending order
7 : 12 < 13 : 18 < 5 : 6 < 8 : 9.

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Chapter 7: Ratio and Proportion - Exercise 1

APPEARS IN

R.S. Aggarwal Mathematics [English] Class 10 ICSE
Chapter 7 Ratio and Proportion
Exercise 1 | Q 2

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