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NCERT Exemplar solutions for Mathematics [English] Class 10 chapter 8 - Introduction To Trigonometry and Its Applications [Latest edition]

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NCERT Exemplar solutions for Mathematics [English] Class 10 chapter 8 - Introduction To Trigonometry and Its Applications - Shaalaa.com
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Solutions for Chapter 8: Introduction To Trigonometry and Its Applications

Below listed, you can find solutions for Chapter 8 of CBSE, Karnataka Board NCERT Exemplar for Mathematics [English] Class 10.


Exercise 8.1Exercise 8.2Exercise 8.3Exercise 8.4
Exercise 8.1

NCERT Exemplar solutions for Mathematics [English] Class 10 8 Introduction To Trigonometry and Its Applications Exercise 8.1

Choose the correct alternative:

1Page 89

If cos A = `4/5`, then the value of tan A is ______.

  • `3/5`

  • `3/4`

  • `4/3`

  • `5/3`

  • `1/8`

2Page 90

If sin A = `1/2`, then the value of cot A is ______.

  • `sqrt(3)`

  • `1/sqrt(3)`

  • `sqrt(3)/2`

  • 1

3Page 90

The value of the expression [cosec(75° + θ) – sec(15° – θ) – tan(55° + θ) + cot(35° – θ)] is ______.

  • – 1

  • 0

  • 1

  • `3/2`

5Page 90

If cos (α + β) = 0, then sin (α – β) can be reduced to ______.

  • cos β

  • cos 2β

  • sin α

  • sin 2α

6Page 90

The value of (tan1° tan2° tan3° ... tan89°) is ______.

  • 0

  • 1

  • 2

  • `1/2`

7Page 90

If cos 9α = sinα and 9α < 90°, then the value of tan5α is ______.

  • `1/sqrt(3)`

  • `sqrt(3)`

  • 1

  • 0

8Page 90

If ∆ABC is right angled at C, then the value of cos (A + B) is ______.

  • 0

  • 1

  • `1/2`

  • `sqrt(3)/2`

9Page 90

If sinA + sin2A = 1, then the value of the expression (cos2A + cos4A) is ______.

  • 1

  • `1/2`

  • 2

  • 3

10Page 90

Given that sinα = `1/2` and cosβ = `1/2`, then the value of (α + β) is ______.

  • 30°

  • 60°

  • 90°

11Page 91

The value of the expression `[(sin^2 22^circ + sin^2 68^circ)/(cos^2 22^circ + cos^2 68^circ) + sin^2 63^circ + cos 63^circ sin 27^circ]` is ______.

  • 3

  • 2

  • 1

  • 0

12Page 91

If 4 tanθ = 3, then `((4 sintheta - costheta)/(4sintheta + costheta))` is equal to ______.

  • `2/3`

  • `1/3`

  • `1/2`

  • `3/4`

13Page 91

If sinθ – cosθ = 0, then the value of (sin4θ + cos4θ) is ______.

  • 1

  • `3/4`

  • `1/2`

  • `1/4`

14Page 91

sin(45° + θ) – cos(45° – θ) is equal to ______.

  • 2cosθ

  • 0

  • 2sinθ

  • 1

15Page 91

A pole 6 m high casts a shadow `2sqrt(3)` m long on the ground, then the Sun’s elevation is ______.

  • 60°

  • 45°

  • 30°

  • 90°

4

Given that sin θ = `a/b` then cos θ is equal to ______.

  • `b/sqrt(b^2 - a^2)`

  • `b/a`

  • `sqrt(b^2 - a^2)/b`

  • `a/sqrt(b^2 - a^2)`

Exercise 8.2 [Page 93]

NCERT Exemplar solutions for Mathematics [English] Class 10 8 Introduction To Trigonometry and Its Applications Exercise 8.2 [Page 93]

State whether the following statement is True or False:

1Page 93

`tan 47^circ/cot 43^circ` = 1

  • True

  • False

2Page 93

The value of the expression (cos2 23° – sin2 67°) is positive.

  • True

  • False

3Page 93

The value of the expression (sin 80° – cos 80°) is negative.

  • True

  • False

4Page 93

`sqrt((1 - cos^2theta) sec^2 theta) = tan theta` 

  • True

  • False

5Page 93

If cosA + cos2A = 1, then sin2A + sin4A = 1.

  • True

  • False

6Page 93

(tan θ + 2)(2 tan θ + 1) = 5 tan θ + sec2θ.

  • True

  • False

7Page 93

If the length of the shadow of a tower is increasing, then the angle of elevation of the sun is also increasing.

  • True

  • False

8Page 93

If a man standing on a platform 3 metres above the surface of a lake observes a cloud and its reflection in the lake, then the angle of elevation of the cloud is equal to the angle of depression of its reflection.

  • True

  • False

9Page 93

The value of 2sinθ can be `a + 1/a`, where a is a positive number, and a ≠ 1.

  • True

  • False

10Page 93

Write True' or False' and justify your answer the following: 

\[ \cos \theta = \frac{a^2 + b^2}{2ab}\]where a and b are two distinct numbers such that ab > 0.

  • True

  • False

11Page 93

The angle of elevation of the top of a tower is 30°. If the height of the tower is doubled, then the angle of elevation of its top will also be doubled.

  • True

  • False

12Page 93

If the height of a tower and the distance of the point of observation from its foot, both, are increased by 10%, then the angle of elevation of its top remains unchanged.

  • True

  • False

Exercise 8.3 [Page 95]

NCERT Exemplar solutions for Mathematics [English] Class 10 8 Introduction To Trigonometry and Its Applications Exercise 8.3 [Page 95]

1Page 95

Prove the following:

`sintheta/(1 + cos theta) + (1 + cos theta)/sintheta` = 2cosecθ

2Page 95

Prove the following:

`tanA/(1 + sec A) - tanA/(1 - sec A)` = 2cosec A

3Page 95

Prove the following:

If tan A = `3/4`, then sinA cosA = `12/25`

4Page 95

Prove the following:

(sin α + cos α)(tan α + cot α) = sec α + cosec α

5Page 95

Prove the following:

`(sqrt(3) + 1) (3 - cot 30^circ)` = tan3 60° – 2 sin 60°

6Page 95

Prove the following:

`1 + (cot^2 alpha)/(1 + "cosec"  alpha)` = cosec α

7Page 95

Prove the following:

tan θ + tan (90° – θ) = sec θ sec (90° – θ)

8Page 95

Find the angle of elevation of the sun when the shadow of a pole h metres high is `sqrt(3)` h metres long.

9Page 95

If `sqrt(3) tan θ` = 1, then find the value of sin2θ – cos2θ.

10Page 95

A ladder 15 metres long just reaches the top of a vertical wall. If the ladder makes an angle of 60° with the wall, find the height of the wall.

11Page 95

Simplify (1 + tan2θ)(1 – sinθ)(1 + sinθ)

12Page 95

If 2sin2θ – cos2θ = 2, then find the value of θ.

13Page 95

Show that `(cos^2(45^circ + θ) + cos^2(45^circ - θ))/(tan(60^circ + θ) tan(30^circ - θ)) = 1`

14Page 95

An observer 1.5 metres tall is 20.5 metres away from a tower 22 metres high. Determine the angle of elevation of the top of the tower from the eye of the observer.

15Page 95

Show that tan4θ + tan2θ = sec4θ – sec2θ.

Exercise 8.4 [Pages 99 - 100]

NCERT Exemplar solutions for Mathematics [English] Class 10 8 Introduction To Trigonometry and Its Applications Exercise 8.4 [Pages 99 - 100]

1Page 99

If cosec θ + cot θ = p, then prove that cos θ = `(p^2 - 1)/(p^2 + 1)`

2Page 99

Prove that `sqrt(sec^2 theta + "cosec"^2 theta) = tan theta + cot theta`

3Page 99

The angle of elevation of the top of a tower from certain point is 30°. If the observer moves 20 metres towards the tower, the angle of elevation of the top increases by 15°. Find the height of the tower.

4Page 99

If 1 + sin2θ = 3 sin θ cos θ, then prove that tan θ = 1 or `1/2`.

5Page 99

Given that sinθ + 2cosθ = 1, then prove that 2sinθ – cosθ = 2.

6Page 99

The angle of elevation of the top of a tower from two points distant s and t from its foot are complementary. Prove that the height of the tower is `sqrt(st)`

7Page 99

The shadow of a tower standing on a level plane is found to be 50 m longer when Sun’s elevation is 30° than when it is 60°. Find the height of the tower.

8Page 99

A vertical tower stands on a horizontal plane and is surmounted by a vertical flag staff of height h. At a point on the plane, the angles of elevation of the bottom and the top of the flag staff are α and β, respectively. Prove that the height of the tower is `((h tan α)/(tan β - tan α))`.

9Page 99

If tan θ + sec θ = l, then prove that sec θ = `(l^2 + 1)/(2l)`.

10Page 99

If sin θ + cos θ = p and sec θ + cosec θ = q, then prove that q(p2 – 1) = 2p.

11Page 99

If a sinθ + b cosθ = c, then prove that a cosθ – b sinθ = `sqrt(a^2 + b^2 - c^2)`.

12Page 99

Prove that `(1 + sec theta - tan theta)/(1 + sec theta + tan theta) = (1 - sin theta)/cos theta`

13Page 99

The angle of elevation of the top of a tower 30 m high from the foot of another tower in the same plane is 60° and the angle of elevation of the top of the second tower from the foot of the first tower is 30°. Find the distance between the two towers and also the height of the other tower.

14Page 100

From the top of a tower h m high, the angles of depression of two objects, which are in line with the foot of the tower are α and β (β > α). Find the distance between the two objects.

15Page 100

A ladder rests against a vertical wall at an inclination α to the horizontal. Its foot is pulled away from the wall through a distance p so that its upper end slides a distance q down the wall and then the ladder makes an angle β to the horizontal. Show that `p/q = (cos β - cos α)/(sin α - sin β)`

16Page 100

The angle of elevation of the top of a vertical tower from a point on the ground is 60°. From another point 10 m vertically above the first, its angle of elevation is 45°. Find the height of the tower.

17Page 100

A window of a house is h metres above the ground. From the window, the angles of elevation and depression of the top and the bottom of another house situated on the opposite side of the lane are found to be α and β, respectively. Prove that the height of the other house is h(1+ tan α tan β) metres.

18Page 100

The lower window of a house is at a height of 2 m above the ground and its upper window is 4 m vertically above the lower window. At certain instant the angles of elevation of a balloon from these windows are observed to be 60° and 30° respectively. Find the height of the balloon above the ground.

Solutions for 8: Introduction To Trigonometry and Its Applications

Exercise 8.1Exercise 8.2Exercise 8.3Exercise 8.4
NCERT Exemplar solutions for Mathematics [English] Class 10 chapter 8 - Introduction To Trigonometry and Its Applications - Shaalaa.com

NCERT Exemplar solutions for Mathematics [English] Class 10 chapter 8 - Introduction To Trigonometry and Its Applications

Shaalaa.com has the CBSE, Karnataka Board Mathematics Mathematics [English] Class 10 CBSE, Karnataka Board solutions in a manner that help students grasp basic concepts better and faster. The detailed, step-by-step solutions will help you understand the concepts better and clarify any confusion. NCERT Exemplar solutions for Mathematics Mathematics [English] Class 10 CBSE, Karnataka Board 8 (Introduction To Trigonometry and Its Applications) include all questions with answers and detailed explanations. This will clear students' doubts about questions and improve their application skills while preparing for board exams.

Further, we at Shaalaa.com provide such solutions so students can prepare for written exams. NCERT Exemplar textbook solutions can be a core help for self-study and provide excellent self-help guidance for students.

Concepts covered in Mathematics [English] Class 10 chapter 8 Introduction To Trigonometry and Its Applications are Trigonometric Ratios, Trigonometric Ratios of Specific Angles, Trigonometric Identities (Square Relations), Trigonometry, Relation Among Trigonometric Ratios, Angles of Elevation and Depression, Problems based on Elevation and Depression.

Using NCERT Exemplar Mathematics [English] Class 10 solutions Introduction To Trigonometry and Its Applications exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in NCERT Exemplar Solutions are essential questions that can be asked in the final exam. Maximum CBSE, Karnataka Board Mathematics [English] Class 10 students prefer NCERT Exemplar Textbook Solutions to score more in exams.

Get the free view of Chapter 8, Introduction To Trigonometry and Its Applications Mathematics [English] Class 10 additional questions for Mathematics Mathematics [English] Class 10 CBSE, Karnataka Board, and you can use Shaalaa.com to keep it handy for your exam preparation.

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