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The value of the expression [cosec(75° + θ) – sec(15° – θ) – tan(55° + θ) + cot(35° – θ)] is ______. - Mathematics

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Question

The value of the expression [cosec(75° + θ) – sec(15° – θ) – tan(55° + θ) + cot(35° – θ)] is ______.

Options

  • – 1

  • 0

  • 1

  • `3/2`

MCQ
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Solution

The value of the expression [cosec(75° + θ) – sec(15° – θ) – tan(55° + θ) + cot(35° – θ)] is 0.

Explanation:

According to the question,

We have to find the value of the equation,

cosec(75° + θ) – sec(15° – θ) – tan(55° + θ) + cot(35° – θ)

= cosec[90° – (15° – θ)] – sec(15° – θ) – tan(55° + θ) + cot[90° – (55° + θ)]

Since, cosec(90° – θ) = sec θ

And cot(90° – θ) = tan θ

We get,

= sec(15° – θ) – sec(15° – θ) – tan(55° + θ) + tan(55° + θ)

= 0

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Chapter 8: Introduction To Trigonometry and Its Applications - Exercise 8.1 [Page 90]

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NCERT Exemplar Mathematics [English] Class 10
Chapter 8 Introduction To Trigonometry and Its Applications
Exercise 8.1 | Q 3 | Page 90

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