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If θ3tanθ = 1, then find the value of sin2θ – cos2θ. - Mathematics

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Question

If `sqrt(3) tan θ` = 1, then find the value of sin2θ – cos2θ.

Sum
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Solution

Given that,

`sqrt(3) tan θ` = 1

⇒ tan θ = `1/sqrt(3)` = tan 30°

⇒ θ = 30°

Now, sin2θ – cos2θ = sin230° – cos230°

= `(1/2)^2 - (sqrt(3)/2)^2`

= `1/4 - 3/4`

= `(1 - 3)/4`

= `-2/4`

= `-1/2`

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Chapter 8: Introduction To Trigonometry and Its Applications - Exercise 8.3 [Page 95]

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NCERT Exemplar Mathematics [English] Class 10
Chapter 8 Introduction To Trigonometry and Its Applications
Exercise 8.3 | Q 9 | Page 95

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