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Tamil Nadu Board of Secondary EducationSSLC (English Medium) Class 10

SSLC (English Medium) Class 10 - Tamil Nadu Board of Secondary Education Question Bank Solutions

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In ΔABC, D and E are points on the sides AB and AC respectively. For the following case show that DE || BC

AB = 12 cm, AD = 8 cm, AE = 12 cm and AC = 18 cm

[4] Geometry
Chapter: [4] Geometry
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In ΔABC, D and E are points on the sides AB and AC respectively. For the following case show that DE || BC

AB = 5.6 cm, AD = 1.4 cm, AC = 7.2 cm and AE = 1.8 cm.

[4] Geometry
Chapter: [4] Geometry
Concept: undefined >> undefined

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If PQ || BC and PR || CD prove that `"AR"/"AD" = "AQ"/"AB"`

[4] Geometry
Chapter: [4] Geometry
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If PQ || BC and PR || CD prove that `"QB"/"AQ" = "DR"/"AR"`

[4] Geometry
Chapter: [4] Geometry
Concept: undefined >> undefined

Rhombus PQRB is inscribed in ΔABC such that ∠B is one of its angle. P, Q and R lie on AB, AC and BC respectively. If AB = 12 cm and BC = 6 cm, find the sides PQ, RB of the rhombus.

[4] Geometry
Chapter: [4] Geometry
Concept: undefined >> undefined

In trapezium ABCD, AB || DC, E and F are points on non-parallel sides AD and BC respectively, such that EF || AB. Show that = `"AE"/"ED" = "BF"/"FC"`

[4] Geometry
Chapter: [4] Geometry
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DE || BC and CD || EE Prove that AD2 = AB × AF

[4] Geometry
Chapter: [4] Geometry
Concept: undefined >> undefined

Check whether AD is bisector of ∠A of ∆ABC of the following
AB = 5 cm, AC = 10 cm, BD = 1.5 cm and CD = 3.5 cm

[4] Geometry
Chapter: [4] Geometry
Concept: undefined >> undefined

Check whether AD is bisector of ∠A of ∆ABC of the following

AB = 4 cm, AC = 6 cm, BD = 1.6 cm and CD = 2.4 cm.

[4] Geometry
Chapter: [4] Geometry
Concept: undefined >> undefined

∠QPR = 90°, PS is its bisector. If ST ⊥ PR, prove that ST × (PQ + PR) = PQ × PR

[4] Geometry
Chapter: [4] Geometry
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ABCD is a quadrilateral in which AB = AD, the bisector of ∠BAC and ∠CAD intersect the sides BC and CD at the points E and F, respectively. Prove that EF || BD.

[4] Geometry
Chapter: [4] Geometry
Concept: undefined >> undefined

Construct a ∆PQR in which the base PQ = 4.5 cm, ∠R = 35° and the median from R to RG is 6 cm.

[4] Geometry
Chapter: [4] Geometry
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Construct a ∆PQR in which QR = 5 cm, ∠P = 40° and the median PG from P to QR is 4.4 cm. Find the length of the altitude from P to QR.

[4] Geometry
Chapter: [4] Geometry
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Construct a ∆PQR such that QR = 6.5 cm, ∠P = 60° and the altitude from P to QR is of length 4.5 cm

[4] Geometry
Chapter: [4] Geometry
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Construct a ∆ABC such that AB = 5.5 cm, ∠C = 25° and the altitude from C to AB is 4 cm

[4] Geometry
Chapter: [4] Geometry
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Draw a triangle ABC of base BC = 5.6 cm, ∠A = 40° and the bisector of ∠A meets BC at D such that CD = 4 cm

[4] Geometry
Chapter: [4] Geometry
Concept: undefined >> undefined

Draw ∆PQR such that PQ = 6.8 cm, vertical angle is 50° and the bisector of the vertical angle meets the base at D where PD = 5.2 cm

[4] Geometry
Chapter: [4] Geometry
Concept: undefined >> undefined

ST || QR, PS = 2 cm and SQ = 3 cm. Then the ratio of the area of ∆PQR to the area of ∆PST is

[4] Geometry
Chapter: [4] Geometry
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ABC is a triangle in which AB = AC. Points D and E are points on the side AB and AC respectively such that AD = AE. Show that the points B, C, E and D lie on a same circle

[4] Geometry
Chapter: [4] Geometry
Concept: undefined >> undefined

An Emu which is 8 feet tall is standing at the foot of a pillar which is 30 feet high. It walks away from the pillar. The shadow of the Emu falls beyond Emu. What is the relation between the length of the shadow and the distance from the Emu to the pillar?

[4] Geometry
Chapter: [4] Geometry
Concept: undefined >> undefined
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