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Tamil Nadu Board of Secondary EducationSSLC (English Medium) Class 10

In ΔABC, D and E are points on the sides AB and AC respectively. For the following case show that DE || BC AB = 12 cm, AD = 8 cm, AE = 12 cm and AC = 18 cm - Mathematics

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Question

In ΔABC, D and E are points on the sides AB and AC respectively. For the following case show that DE || BC

AB = 12 cm, AD = 8 cm, AE = 12 cm and AC = 18 cm

Sum
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Solution

Here AB = 12 cm, BD =12 – 8 = 4 cm, AE =12 cm, EC = 18 – 12 = 6 cm

∴ `"AD"/"DB" = 8/4` = 2

`"AE"/"EC" = 12/6` = 2

`"AD"/"DB" = "AE"/"EC"`

By converse of basic proportionality theorem DE || BC

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Thales Theorem and Angle Bisector Theorem
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Chapter 4: Geometry - Exercise 4.2 [Page 182]

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Samacheer Kalvi Mathematics [English] Class 10 SSLC TN Board
Chapter 4 Geometry
Exercise 4.2 | Q 3. (i) | Page 182
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