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Question
An Emu which is 8 feet tall is standing at the foot of a pillar which is 30 feet high. It walks away from the pillar. The shadow of the Emu falls beyond Emu. What is the relation between the length of the shadow and the distance from the Emu to the pillar?
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Solution
Let the shadow of the emu AE be “x” and BE be “y” ED || BC
By basic proportionality theorem
`"AE"/"AB" = "ED"/"BC"`
`x/(x + y) = 8/30`
30x = 8x + 8y
22x – 8y = 0
11x – 4y = 0 ...(÷ by 2)
11x = 4y
x = `4/11 xx y`
x = `4/11` × distance from the pillar to emu
Length of = `4/11` × distance from the shadow the pillar to emu
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