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तामिळनाडू बोर्ड ऑफ सेकेंडरी एज्युकेशनएस.एस.एल.सी. (इंग्रजी माध्यम) इयत्ता १०

An Emu which is 8 feet tall is standing at the foot of a pillar which is 30 feet high. It walks away from the pillar. The shadow of the Emu falls beyond Emu. What is the relation between the lengt

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प्रश्न

An Emu which is 8 feet tall is standing at the foot of a pillar which is 30 feet high. It walks away from the pillar. The shadow of the Emu falls beyond Emu. What is the relation between the length of the shadow and the distance from the Emu to the pillar?

बेरीज
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उत्तर

Let the shadow of the emu AE be “x” and BE be “y” ED || BC

By basic proportionality theorem

`"AE"/"AB" = "ED"/"BC"`

`x/(x + y) = 8/30`

30x = 8x + 8y

22x – 8y = 0

11x – 4y = 0   ...(÷ by 2)

11x = 4y

x = `4/11 xx y`

x = `4/11` × distance from the pillar to emu

Length of = `4/11` × distance from the shadow the pillar to emu

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Thales Theorem and Angle Bisector Theorem
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पाठ 4: Geometry - Unit Exercise – 4 [पृष्ठ २०१]

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सामाचीर कलवी Mathematics [English] Class 10 SSLC TN Board
पाठ 4 Geometry
Unit Exercise – 4 | Q 8 | पृष्ठ २०१

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