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तामिळनाडू बोर्ड ऑफ सेकेंडरी एज्युकेशनएस.एस.एल.सी. (इंग्रजी माध्यम) इयत्ता १०

Rhombus PQRB is inscribed in ΔABC such that ∠B is one of its angle. P, Q and R lie on AB, AC and BC respectively. If AB = 12 cm and BC = 6 cm, find the sides PQ, RB of the rhombus. - Mathematics

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प्रश्न

Rhombus PQRB is inscribed in ΔABC such that ∠B is one of its angle. P, Q and R lie on AB, AC and BC respectively. If AB = 12 cm and BC = 6 cm, find the sides PQ, RB of the rhombus.

बेरीज
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उत्तर

Let the side of the rhombus be “x”. Since PQRB is a

Rhombus PQ || BC

By basic proportionality theorem


`"AP"/"AB" = "PQ"/"BC" ⇒ (12 - x)/"BC" = x/6`

12x = 6(12 – x)

12x = 72 – 6x

12x + 6x = 72

18x = 72 ⇒ x = `72/18` = 4

Side of a rhombus = 4 cm

PQ = RB = 4 cm

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Thales Theorem and Angle Bisector Theorem
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पाठ 4: Geometry - Exercise 4.2 [पृष्ठ १८२]

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सामाचीर कलवी Mathematics [English] Class 10 SSLC TN Board
पाठ 4 Geometry
Exercise 4.2 | Q 5 | पृष्ठ १८२

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