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प्रश्न
ST || QR, PS = 2 cm and SQ = 3 cm. Then the ratio of the area of ∆PQR to the area of ∆PST is
पर्याय
25 : 4
25 : 7
25 : 11
25 : 13
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उत्तर
25 : 4
Explanation;
Hint:
Area of ∆PQR : Area of ∆PST
`("Area of" Delta"PQR")/("Area of" Delta"PST") = "PQ"^2/"PS"^2 = 5^2/2^2 = 25/4`
Area of ∆PQR : Area of ∆PST = 25 : 4
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