Advertisements
Advertisements
प्रश्न
If PQ || BC and PR || CD prove that `"QB"/"AQ" = "DR"/"AR"`
Advertisements
उत्तर
In ∆ABC, PQ || BC ...(Given)
By basic proportionality theorem
`"AP"/"PC" = "AQ"/"QB"` ...(1)
In ∆ADC, PR || CD ...(Given)
By basic proportionality theorem
`"AP"/"PC" = "AR"/"RD"` ...(2)
From (1) and (2) we get
`"AQ"/"QB" = "AP"/"RD"`
or
`"QB"/"AQ" = "DR"/"AR"`
APPEARS IN
संबंधित प्रश्न
In ∆ABC, D and E are points on the sides AB and AC respectively such that DE || BC
If `"AD"/"DB" = 3/4` and AC = 15 cm find AE
In ΔABC, D and E are points on the sides AB and AC respectively. For the following case show that DE || BC
AB = 12 cm, AD = 8 cm, AE = 12 cm and AC = 18 cm
In ΔABC, D and E are points on the sides AB and AC respectively. For the following case show that DE || BC
AB = 5.6 cm, AD = 1.4 cm, AC = 7.2 cm and AE = 1.8 cm.
If PQ || BC and PR || CD prove that `"AR"/"AD" = "AQ"/"AB"`
Rhombus PQRB is inscribed in ΔABC such that ∠B is one of its angle. P, Q and R lie on AB, AC and BC respectively. If AB = 12 cm and BC = 6 cm, find the sides PQ, RB of the rhombus.
DE || BC and CD || EE Prove that AD2 = AB × AF
∠QPR = 90°, PS is its bisector. If ST ⊥ PR, prove that ST × (PQ + PR) = PQ × PR
Construct a ∆PQR such that QR = 6.5 cm, ∠P = 60° and the altitude from P to QR is of length 4.5 cm
Draw a triangle ABC of base BC = 5.6 cm, ∠A = 40° and the bisector of ∠A meets BC at D such that CD = 4 cm
An Emu which is 8 feet tall is standing at the foot of a pillar which is 30 feet high. It walks away from the pillar. The shadow of the Emu falls beyond Emu. What is the relation between the length of the shadow and the distance from the Emu to the pillar?
