English
Tamil Nadu Board of Secondary EducationSSLC (English Medium) Class 10

Construct a ∆PQR in which the base PQ = 4.5 cm, ∠R = 35° and the median from R to RG is 6 cm.

Advertisements
Advertisements

Question

Construct a ∆PQR in which the base PQ = 4.5 cm, ∠R = 35° and the median from R to RG is 6 cm.

Diagram
Sum
Advertisements

Solution



Steps of construction:

1. Draw a line segment PQ = 4.5 cm

2. At P, draw PE such that ∠QPE = 60°

3. At P, draw PF such that ∠EPF = 90°

4. Draw the perpendicular bisect to PQ, which intersects PF at O and PQ at G.

5. With O as centre and OP as radius draw a circle.

6. From G mark arcs of radius 5.8 cm on the circle. Mark them at R and S

7. Join PR and RQ.

8. PQR is the required triangle.

shaalaa.com
Thales Theorem and Angle Bisector Theorem
  Is there an error in this question or solution?
Chapter 4: Geometry - Exercise 4.2 [Page 182]

APPEARS IN

Samacheer Kalvi Mathematics [English] Class 10 SSLC TN Board
Chapter 4 Geometry
Exercise 4.2 | Q 11 | Page 182

RELATED QUESTIONS

In ∆ABC, D and E are points on the sides AB and AC respectively such that DE || BC

If AD = 8x – 7, DB = 5x – 3, AE = 4x – 3 and EC = 3x – 1, find the value of x


In ΔABC, D and E are points on the sides AB and AC respectively. For the following case show that DE || BC

AB = 12 cm, AD = 8 cm, AE = 12 cm and AC = 18 cm


Rhombus PQRB is inscribed in ΔABC such that ∠B is one of its angle. P, Q and R lie on AB, AC and BC respectively. If AB = 12 cm and BC = 6 cm, find the sides PQ, RB of the rhombus.


Check whether AD is bisector of ∠A of ∆ABC of the following
AB = 5 cm, AC = 10 cm, BD = 1.5 cm and CD = 3.5 cm


Check whether AD is bisector of ∠A of ∆ABC of the following

AB = 4 cm, AC = 6 cm, BD = 1.6 cm and CD = 2.4 cm.


Construct a ∆PQR such that QR = 6.5 cm, ∠P = 60° and the altitude from P to QR is of length 4.5 cm


Construct a ∆ABC such that AB = 5.5 cm, ∠C = 25° and the altitude from C to AB is 4 cm


Draw a triangle ABC of base BC = 5.6 cm, ∠A = 40° and the bisector of ∠A meets BC at D such that CD = 4 cm


An Emu which is 8 feet tall is standing at the foot of a pillar which is 30 feet high. It walks away from the pillar. The shadow of the Emu falls beyond Emu. What is the relation between the length of the shadow and the distance from the Emu to the pillar?


Two circles intersect at A and B. From a point, P on one of the circles lines PAC and PBD are drawn intersecting the second circle at C and D. Prove that CD is parallel to the tangent at P.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×