SSLC (English Medium) Class 10 - Tamil Nadu Board of Secondary Education Question Bank Solutions for Mathematics

Let A = {1, 2, 3} and B = {x | x is a prime number less than 10}. Find A × B and B × A

If B × A = {(-2, 3), (-2, 4), (0, 3), (0, 4), (3, 3), (3, 4)} find A and B

Multiple Choice Question :

If the ordered pairs (a + 2, 4) and (5, 2a + b) are equal then (a, b) is

If the ordered pairs (x² – 3x, y² + 4y) and (– 2, 5) are equal, then find x and y

Find all positive integers, when divided by 3 leaves remainder 2

Prove that the product of two consecutive positive integers is divisible by 2

When the positive integers a, b and c are divided by 13, the respective remainders are 9, 7 and 10. Show that a + b + c is divisible by 13

Prove that square of any integer leaves the remainder either 0 or 1 when divided by 4

If d is the Highest Common Factor of 32 and 60, find x and y satisfying d = 32x + 60y

A positive integer, when divided by 88, gives the remainder 61. What will be the remainder when the same number is divided by 11?

Prove that two consecutive positive integers are always co-prime

Euclid’s division lemma states that for positive integers a and b, there exist unique integers q and r such that a = bq + r, where r must satisfy

Using Euclid’s division lemma, if the cube of any positive integer is divided by 9 then the possible remainders are

Prove that n² – n divisible by 2 for every positive integer n

When the positive integers a, b and c are divided by 13 the respective remainders is 9, 7 and 10. Find the remainder when a b + + 2 3c is divided by 13

Show that 107 is of the form  4q +3 for any integer q

Solve the following system of linear equations in three variables

x + y + z = 5; 2x – y + z = 9; x – 2y + 3z = 16

Solve the following system of linear equations in three variables

`1/x - 2/y + 4 = 0; 1/y - 1/z + 1 = 0; 2/z + 3/x = 14`

Solve the following system of linear equations in three variables

x + 20 = `(3y)/2 + 10` = 2z + 5 = 110 – (y + z)

Discuss the nature of solutions of the following system of equations

x + 2y – z = 6; – 3x – 2y + 5z = – 12; x – 2z = 3