SSC (English Medium) 8th Standard - Maharashtra State Board Question Bank Solutions

Expand.

(58)³

Expand.

(198)³

Expand.

`(2p - 1/(2p))^3`

Expand.

`(1 - 1/a)^3`

Expand.

`(x/3 - 3/x)^3`

In ☐ABCD, l(AB) = 13 cm, l(DC) = 9 cm, l(AD) = 8 cm, find the area of ☐ABCD.

Simplify:

\[\frac{8 x^3 - 27 y^3}{4 x^2 - 9 y^2}\]

Simplify:

\[\frac{m^2 - n^2}{\left( m + n \right)^2} \times \frac{m^2 + mn + n^2}{m^3 - n^3}\]

Simplify:

\[\frac{a^2 + 10a + 21}{a^2 + 6a - 7} \times \frac{a^2 - 1}{a + 3}\]

Simplify:

\[\frac{x^2 - 5x - 24}{\left( x + 3 \right)\left( x + 8 \right)} \times \frac{x^2 - 64}{\left( x - 8 \right)^2}\]

Simplify:

\[\frac{3 x^2 - x - 2}{x^2 - 7x + 12} \div \frac{3 x^2 - 7x - 6}{x^2 - 4}\]

Simplify:

\[\frac{4 x^2 - 11x + 6}{16 x^2 - 9}\]

Simplify:

\[\frac{a^3 - 27}{5 a^2 - 16a + 3} \div \frac{a^2 + 3a + 9}{25 a^2 - 1}\]

Simplify:

`(1 - 2x + x^2)/(1 - x^3) xx (1 + x + x^2)/(1 + x)`

Factorise:

y³ − 27

Factorise:

x³ − 64y³

Factorise:

27m³ − 216n³

Factorise:

125y³ − 1

Factorise:

8p³ −\[\frac{27}{p^3}\]

Factorise:

343a³ − 512b³