HSC Commerce (English Medium) 12th Standard Board Exam - Maharashtra State Board Question Bank Solutions

Find `(dy)/(dx) , "If"   x^3 + y^2 + xy = 10`

Find `(dy)/(dx) if y = cos^-1 (√x)`

Find `(dy)/(dx)` if `y = sin^-1(sqrt(1-x^2))`

Differentiate tan^-1 (cot 2x) w.r.t.x.

If x = tan^-1t and y = t³ , find `(dy)/(dx)`.

Discuss extreme values of the function f(x) = x.logx

If e^x + e^y = e^{(x + y)}, then show that `dy/dx = -e^(y - x)`.

If `sin^-1((x^5 - y^5)/(x^5 + y^5)) = pi/(6), "show that" "dy"/"dx" = x^4/(3y^4)`

If y = `sqrt(cosx + sqrt(cosx + sqrt(cosx + ... ∞)`, then show that `"dy"/"dx" = sinx/(1 - 2y)`.

Find `"dy"/"dx"` if x = at², y = 2at.

Find `"dy"/"dx"` if x = a cot θ, y = b cosec θ

Find `"dy"/"dx"`, if : x = `sqrt(a^2 + m^2), y = log(a^2 + m^2)`

Find `"dy"/"dx"`, if : x = sinθ, y = tanθ

Find `"dy"/"dx"`, if : x = a(1 – cosθ), y = b(θ – sinθ)

Find `"dy"/"dx"`, if : x = `(t + 1/t)^a, y = a^(t+1/t)`, where a > 0, a ≠ 1, t ≠ 0.

Find `"dy"/"dx"`, if : `x = cos^-1((2t)/(1 + t^2)), y = sec^-1(sqrt(1 + t^2))`

Find `"dy"/"dx"`, if : `x = cos^-1(4t^3 - 3t), y = tan^-1(sqrt(1 - t^2)/t)`.

Find `"dy"/"dx"` if : x = cosec²θ, y = cot³θ at θ= `pi/(6)`

Find `"dy"/"dx"` if : x = a cos³θ, y = a sin³θ at θ = `pi/(3)`

Find `"dy"/"dx"` if : x = t² + t + 1, y = `sin((pit)/2) + cos((pit)/2) "at"  t = 1`