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Give plausible explanation for the following:
Cyclohexanone forms cyanohydrin in good yield but 2, 2, 6 trimethylcyclohexanone does not.
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Give plausible explanation for the following:
There are two −NH2 groups in semicarbazide. However, only one is involved in the formation of semicarbazones.
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Complete the synthesis by giving missing starting material, reagent or product.
\[\ce{C6H5CHO ->[H2NCONHNH2]}\]
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Complete the synthesis by giving missing starting material, reagent or product.

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Give the equations of reactions for the preparation of phenol from cumene.
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Write chemical reaction for the preparation of phenol from chlorobenzene.
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You are given benzene, conc. H2SO4 and NaOH. Write the equations for the preparation of phenol using these reagents.
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Write the equation for the preparation of 1-iodobutane from but-1-ene.
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How will you bring about the following conversion?
Ethane to bromoethene
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How the following conversion can be carried out?
Aniline to chlorobenzene
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What happens when white phosphorus is heated with concentrated NaOH solution in an inert atmosphere of CO2?
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Write the reaction involved when D-glucose is treated with the following reagent:
Br2 water
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What happens when D-glucose is treated with the following reagent?
HI
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Amongst the following compounds, identify which are insoluble, partially soluble and highly soluble in water?
- phenol
- toluene
- formic acid
- ethylene glycol
- chloroform
- pentanol
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Give an example of the reaction in the following case.
Oxime
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Give an example of the reaction in the following case.
Imine
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Sucrose decomposes in acid solution to give glucose and fructose according to the first order rate law. The half life of the reaction is 3 hours. Calculate fraction of sucrose which will remain after 8 hours.
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Arrange the following in increasing order of their basic strength in aqueous solution:
\[\ce{CH3NH2, (CH3)3N, (CH3)2NH}\]
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For a first order reaction, show that time required for 99% completion is twice the time required for the completion of 90% of reaction.
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(b) Rate constant ‘k’ of a reaction varies with temperature ‘T’ according to the equation:
`logk=logA-E_a/2.303R(1/T)`
Where Ea is the activation energy. When a graph is plotted for `logk Vs. 1/T` a straight line with a slope of −4250 K is obtained. Calculate ‘Ea’ for the reaction.(R = 8.314 JK−1 mol−1)
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