English Medium Class 9 - CBSE Question Bank Solutions

If \[x + \frac{1}{x} = 2\], then \[x^3 + \frac{1}{x^3} =\]

If \[x + \frac{1}{x}\] 4, then \[x^4 + \frac{1}{x^4} =\]

If \[x + \frac{1}{x} = 3\] then \[x^6 + \frac{1}{x^6}\] = 

If \[x^2 + \frac{1}{x^2} = 102\], then \[x - \frac{1}{x}\] = 

If \[x^3 + \frac{1}{x^3} = 110\], then \[x + \frac{1}{x} =\]

If \[x^3 - \frac{1}{x^3} = 14\],then \[x - \frac{1}{x} =\]

If a + b + c = 9 and ab + bc + ca = 23, then a² + b² + c² =

(a − b)³ + (b − c)³ + (c − a)³ =

If \[\frac{a}{b} + \frac{b}{a} = - 1\] then a³ − b³ =

If a − b = −8 and ab  = −12, then a³ − b³ =

If the volume of a cuboid is 3x² − 27, then its possible dimensions are

75 × 75 + 2 × 75 × 25 + 25 × 25 is equal to

(x − y) (x + y) (x² + y²) (x⁴ + y⁴) is equal to ______.

If \[x^4 + \frac{1}{x^4} = 623\] then \[x + \frac{1}{x} =\]

If  \[x^4 + \frac{1}{x^4} = 194,\] then \[x^3 + \frac{1}{x^3} =\]

If \[x - \frac{1}{x} = \frac{15}{4}\], then \[x + \frac{1}{x}\] = 

If  \[3x + \frac{2}{x} = 7\] , then \[\left( 9 x^2 - \frac{4}{x^2} \right) =\]

If a² + b² + c² − ab − bc − ca =0, then

If a + b + c = 0, then \[\frac{a^2}{bc} + \frac{b^2}{ca} + \frac{c^2}{ab} =\]

If a^1/3 + b^1/3 + c^1/3 = 0, then