Advertisements
Advertisements
Question
If a + b + c = 0, then \[\frac{a^2}{bc} + \frac{b^2}{ca} + \frac{c^2}{ab} =\]
Options
0
1
-1
3
Advertisements
Solution
We have to find `a^2/(bc)+ b^2 /(ca) +c^2 /(ab)`
Given a + b + c = 0
Using identity `a^3 +b^3 +c^3 -3abc = (a+b+c)(a^2 +b^2 +c^2 -ab -bc -ca)`
`a^3 +b^3 +c^3 -3abc = 0 (a^2 +b^2 +c^2 -ab -bc -ca)`
`a^3 +b^3 +c^3 - 3abc = 0 `
`a^3 +b^3 + c^3 = 3abc`
`a^3 /(abc)+ b^3/(abc) +c^3 /(abc ) = 3`
`((a xx a xx a)/(a xx b xx c))+ ((b xx b xx b)/(a xx b xx c))+((c xx c xx c)/(a xx b xx c)) = 3 `
`a^2 /(abc)+ b^2/(abc) +c^2 /(abc ) = 3`
Hence the value of `a^2 /(bc)+ b^2/(ac) +c^2 /(ab ) = 3`.
APPEARS IN
RELATED QUESTIONS
Evaluate the following product without multiplying directly:
103 × 107
Evaluate the following product without multiplying directly:
104 × 96
Give possible expression for the length and breadth of the following rectangle, in which their area is given:
| Area : 35y2 + 13y – 12 |
if `x + 1/x = 11`, find the value of `x^2 + 1/x^2`
If a + b + c = 0 and a2 + b2 + c2 = 16, find the value of ab + bc + ca.
Find the cube of the following binomials expression :
\[\frac{1}{x} + \frac{y}{3}\]
Evaluate of the following:
463+343
Find the value of 27x3 + 8y3, if 3x + 2y = 20 and xy = \[\frac{14}{9}\]
If x = 3 and y = − 1, find the values of the following using in identify:
(9y2 − 4x2) (81y4 +36x2y2 + 16x4)
If a − b = 5 and ab = 12, find the value of a2 + b2
Mark the correct alternative in each of the following:
If \[x + \frac{1}{x} = 5\] then \[x^2 + \frac{1}{x^2} = \]
If \[x - \frac{1}{x} = \frac{15}{4}\], then \[x + \frac{1}{x}\] =
Use identities to evaluate : (101)2
Evaluate : (4a +3b)2 - (4a - 3b)2 + 48ab.
Use the direct method to evaluate the following products :
(8 – b) (3 + b)
Expand the following:
(a + 4) (a + 7)
Expand the following:
(m + 8) (m - 7)
Without actually calculating the cubes, find the value of:
(0.2)3 – (0.3)3 + (0.1)3
Find the value of x3 + y3 – 12xy + 64, when x + y = – 4
