Advertisements
Advertisements
Question
If a + b + c = 0, then \[\frac{a^2}{bc} + \frac{b^2}{ca} + \frac{c^2}{ab} =\]
Options
0
1
-1
3
Advertisements
Solution
We have to find `a^2/(bc)+ b^2 /(ca) +c^2 /(ab)`
Given a + b + c = 0
Using identity `a^3 +b^3 +c^3 -3abc = (a+b+c)(a^2 +b^2 +c^2 -ab -bc -ca)`
`a^3 +b^3 +c^3 -3abc = 0 (a^2 +b^2 +c^2 -ab -bc -ca)`
`a^3 +b^3 +c^3 - 3abc = 0 `
`a^3 +b^3 + c^3 = 3abc`
`a^3 /(abc)+ b^3/(abc) +c^3 /(abc ) = 3`
`((a xx a xx a)/(a xx b xx c))+ ((b xx b xx b)/(a xx b xx c))+((c xx c xx c)/(a xx b xx c)) = 3 `
`a^2 /(abc)+ b^2/(abc) +c^2 /(abc ) = 3`
Hence the value of `a^2 /(bc)+ b^2/(ac) +c^2 /(ab ) = 3`.
APPEARS IN
RELATED QUESTIONS
Factorise the following using appropriate identity:
4y2 – 4y + 1
Expand the following, using suitable identity:
(x + 2y + 4z)2
Without actually calculating the cubes, find the value of the following:
(–12)3 + (7)3 + (5)3
If 3x - 7y = 10 and xy = -1, find the value of `9x^2 + 49y^2`
Simplify of the following:
(2x − 5y)3 − (2x + 5y)3
If a + b = 6 and ab = 20, find the value of a3 − b3
If a + b + c = 0, then write the value of \[\frac{a^2}{bc} + \frac{b^2}{ca} + \frac{c^2}{ab}\]
If a1/3 + b1/3 + c1/3 = 0, then
The number x is 2 more than the number y. If the sum of the squares of x and y is 34, then find the product of x and y.
Use the direct method to evaluate the following products:
(a – 8) (a + 2)
Use the direct method to evaluate :
(2a+3) (2a−3)
Evaluate: (2a + 0.5) (7a − 0.3)
Evaluate: 20.8 × 19.2
Evaluate the following without multiplying:
(1005)2
Evaluate, using (a + b)(a - b)= a2 - b2.
399 x 401
If x + y = 9, xy = 20
find: x2 - y2.
If m - n = 0.9 and mn = 0.36, find:
m + n
If a2 - 3a - 1 = 0 and a ≠ 0, find : `"a" - (1)/"a"`
Prove that (a + b + c)3 – a3 – b3 – c3 = 3(a + b)(b + c)(c + a).
