Use Identities to Evaluate : (101)2

Use identities to evaluate : (101)²

Sum

(101)²
(101)² = (100 + 1)²
We know that,
(a + b)² = a² + b² + 2ab
∴ (100 + 1)² = 100² + 1² + 2 x 100 x 1
= 10,000 + 1 + 200
= 10,201

shaalaa.com

Is there an error in this question or solution?

Chapter 4: Expansions (Including Substitution) - Exercise 4 (A) [Page 57]

Chapter 4 Expansions (Including Substitution)
Exercise 4 (A) | Q 2.1 | Page 57

Use suitable identity to find the following product:

`(y^2+3/2)(y^2-3/2)`

Factorise:

27x³ + y³ + z³ – 9xyz

If x + y + z = 0, show that x³ + y³ + z³ = 3xyz.

If `x - 1/x = 3 + 2sqrt2`, find the value of `x^3 - 1/x^3`

Find the following product:

\[\left( 3 + \frac{5}{x} \right) \left( 9 - \frac{15}{x} + \frac{25}{x^2} \right)\]

If a + b + c = 9 and ab +bc + ca = 26, find the value of a³ + b³+ c³ − 3abc

If \[x^2 + \frac{1}{x^2} = 102\], then \[x - \frac{1}{x}\] =

If x + y = `7/2 "and xy" =5/2`; find: x - y and x² - y²

Use the direct method to evaluate the following products :
(b – 3) (b – 5)

Multiply x² + 4y² + z² + 2xy + xz – 2yz by (–z + x – 2y).