Use Identities to Evaluate : (101)2

Use identities to evaluate : (101)²

Sum

(101)²
(101)² = (100 + 1)²
We know that,
(a + b)² = a² + b² + 2ab
∴ (100 + 1)² = 100² + 1² + 2 x 100 x 1
= 10,000 + 1 + 200
= 10,201

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Chapter 4: Expansions - Exercise 4 (A) [Page 57]

Chapter 4 Expansions
Exercise 4 (A) | Q 2.1 | Page 57

Evaluate following using identities:

(a - 0.1) (a + 0.1)

Evaluate of the following:

(103)³

Simplify of the following:

(2x − 5y)³ − (2x + 5y)³

Find the following product:

\[\left( \frac{x}{2} + 2y \right) \left( \frac{x^2}{4} - xy + 4 y^2 \right)\]

If a + b + c = 0, then write the value of \[\frac{a^2}{bc} + \frac{b^2}{ca} + \frac{c^2}{ab}\]

If a + b + c = 9 and ab + bc + ca = 23, then a² + b² + c² =

If a + b + c = 0, then \[\frac{a^2}{bc} + \frac{b^2}{ca} + \frac{c^2}{ab} =\]

Use the direct method to evaluate :
`("z"-2/3)("z"+2/3)`

If `"a"^2 - 7"a" + 1` = 0 and a = ≠ 0, find :

`"a"^2 + (1)/"a"^2`

If 2x + 3y = 10 and xy = 5; find the value of 4x² + 9y²