Advertisements
Advertisements
प्रश्न
Use identities to evaluate : (101)2
बेरीज
Advertisements
उत्तर
(101)2
(101)2 = (100 + 1)2
We know that,
(a + b)2 = a2 + b2 + 2ab
∴ (100 + 1)2 = 1002 + 12 + 2 x 100 x 1
= 10,000 + 1 + 200
= 10,201
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
Evaluate of the following:
(99)3
Evaluate of the following:
933 − 1073
Simplify of the following:
(2x − 5y)3 − (2x + 5y)3
If a + b = 8 and ab = 6, find the value of a3 + b3
If x + \[\frac{1}{x}\] = then find the value of \[x^2 + \frac{1}{x^2}\].
If a + `1/a`= 6 and a ≠ 0 find :
(i) `a - 1/a (ii) a^2 - 1/a^2`
Expand the following:
(a + 4) (a + 7)
Expand the following:
(a + 3b)2
Using suitable identity, evaluate the following:
101 × 102
Factorise the following:
`(2x + 1/3)^2 - (x - 1/2)^2`
