Advertisements
Advertisements
प्रश्न
Use identities to evaluate : (101)2
Advertisements
उत्तर
(101)2
(101)2 = (100 + 1)2
We know that,
(a + b)2 = a2 + b2 + 2ab
∴ (100 + 1)2 = 1002 + 12 + 2 x 100 x 1
= 10,000 + 1 + 200
= 10,201
APPEARS IN
संबंधित प्रश्न
Evaluate the following product without multiplying directly:
103 × 107
What are the possible expressions for the dimensions of the cuboids whose volume is given below?
| Volume : 3x2 – 12x |
Evaluate the following using identities:
(2x + y) (2x − y)
Find the value of 64x3 − 125z3, if 4x − 5z = 16 and xz = 12.
If `x - 1/x = 3 + 2sqrt2`, find the value of `x^3 - 1/x^3`
Find the following product:
(3x + 2y + 2z) (9x2 + 4y2 + 4z2 − 6xy − 4yz − 6zx)
The product (a + b) (a − b) (a2 − ab + b2) (a2 + ab + b2) is equal to
Find the square of `(3a)/(2b) - (2b)/(3a)`.
If x + y = 1 and xy = -12; find:
x - y
If a + b + c = 5 and ab + bc + ca = 10, then prove that a3 + b3 + c3 – 3abc = – 25.
