Use Identities to Evaluate : (101)2

Use identities to evaluate : (101)²

बेरीज

(101)²
(101)² = (100 + 1)²
We know that,
(a + b)² = a² + b² + 2ab
∴ (100 + 1)² = 100² + 1² + 2 x 100 x 1
= 10,000 + 1 + 200
= 10,201

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पाठ 4: Expansions - Exercise 4 (A) [पृष्ठ ५७]

पाठ 4 Expansions
Exercise 4 (A) | Q 2.1 | पृष्ठ ५७

Evaluate the following product without multiplying directly:

104 × 96

Expand the following, using suitable identity:

(–2x + 3y + 2z)²

Find the cube of the following binomials expression :

\[\frac{1}{x} + \frac{y}{3}\]

Evaluate of the following:

104³ + 96³

Find the value of 27x³ + 8y³, if 3x + 2y = 14 and xy = 8

Use the direct method to evaluate the following products :
(8 – b) (3 + b)

Use the direct method to evaluate :
(2a+3) (2a−3)

Evaluate: 203 × 197

If a² - 3a - 1 = 0 and a ≠ 0, find : `"a"^2 - (1)/"a"^2`

If `x/y + y/x = -1 (x, y ≠ 0)`, the value of x³ – y³ is ______.