Advertisements
Advertisements
प्रश्न
Find the square of `(3a)/(2b) - (2b)/(3a)`.
Advertisements
उत्तर
We know that,
(a - b)2 = a2 + b2 - 2ab
`(3a)/(2b) - (2b)/(3a) = [(3a)/(2b)]^2 + [(2b)/(3a)]^2 - 2 xx (3a)/(2b) xx (2b)/(3a)`
= `(9a^2)/(4b^2) + (4b^2)/(9a^2) - 2`
APPEARS IN
संबंधित प्रश्न
Factorise:
27x3 + y3 + z3 – 9xyz
Evaluate following using identities:
(a - 0.1) (a + 0.1)
Simplify the following products:
`(x/2 - 2/5)(2/5 - x/2) - x^2 + 2x`
Write in the expand form: `(2x - y + z)^2`
If \[x - \frac{1}{x} = - 1\] find the value of \[x^2 + \frac{1}{x^2}\]
Simplify of the following:
If x = 3 and y = − 1, find the values of the following using in identify:
\[\left( \frac{x}{y} - \frac{y}{3} \right) \frac{x^2}{16} + \frac{xy}{12} + \frac{y^2}{9}\]
Mark the correct alternative in each of the following:
If \[x + \frac{1}{x} = 5\] then \[x^2 + \frac{1}{x^2} = \]
Use identities to evaluate : (502)2
If `"a" + 1/"a" = 6;`find `"a"^2 - 1/"a"^2`
