Advertisements
Advertisements
प्रश्न
Find the square of `(3a)/(2b) - (2b)/(3a)`.
Advertisements
उत्तर
We know that,
(a - b)2 = a2 + b2 - 2ab
`(3a)/(2b) - (2b)/(3a) = [(3a)/(2b)]^2 + [(2b)/(3a)]^2 - 2 xx (3a)/(2b) xx (2b)/(3a)`
= `(9a^2)/(4b^2) + (4b^2)/(9a^2) - 2`
APPEARS IN
संबंधित प्रश्न
If 9x2 + 25y2 = 181 and xy = −6, find the value of 3x + 5y
Write in the expanded form:
`(a/(bc) + b/(ca) + c/(ab))^2`
If a2 + b2 + c2 = 16 and ab + bc + ca = 10, find the value of a + b + c.
Evaluate of the following:
(103)3
Evaluate of the following:
`(10.4)^3`
Find the following product:
(3x + 2y + 2z) (9x2 + 4y2 + 4z2 − 6xy − 4yz − 6zx)
Mark the correct alternative in each of the following:
If \[x + \frac{1}{x} = 5\] then \[x^2 + \frac{1}{x^2} = \]
If 49a2 − b = \[\left( 7a + \frac{1}{2} \right) \left( 7a - \frac{1}{2} \right)\] then the value of b is
If x + y = `7/2 "and xy" =5/2`; find: x - y and x2 - y2
If `"a"^2 - 7"a" + 1` = 0 and a = ≠ 0, find :
`"a"^2 + (1)/"a"^2`
