Advertisements
Advertisements
प्रश्न
Use identities to evaluate : (101)2
Advertisements
उत्तर
(101)2
(101)2 = (100 + 1)2
We know that,
(a + b)2 = a2 + b2 + 2ab
∴ (100 + 1)2 = 1002 + 12 + 2 x 100 x 1
= 10,000 + 1 + 200
= 10,201
APPEARS IN
संबंधित प्रश्न
Use suitable identity to find the following product:
(x + 4) (x + 10)
Use suitable identity to find the following product:
(3 – 2x) (3 + 2x)
Factorise the following using appropriate identity:
4y2 – 4y + 1
Write in the expanded form: (ab + bc + ca)2
Evaluate of the following:
`(10.4)^3`
If \[x + \frac{1}{x} = 3\], calculate \[x^2 + \frac{1}{x^2}, x^3 + \frac{1}{x^3}\] and \[x^4 + \frac{1}{x^4}\]
Simplify of the following:
Find the following product:
(3x + 2y + 2z) (9x2 + 4y2 + 4z2 − 6xy − 4yz − 6zx)
If `x + (1)/x = 3`; find `x^2 + (1)/x^2`
Expand the following:
`(4 - 1/(3x))^3`
