Advertisements
Advertisements
प्रश्न
Use identities to evaluate : (101)2
योग
Advertisements
उत्तर
(101)2
(101)2 = (100 + 1)2
We know that,
(a + b)2 = a2 + b2 + 2ab
∴ (100 + 1)2 = 1002 + 12 + 2 x 100 x 1
= 10,000 + 1 + 200
= 10,201
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Write the expanded form:
`(-3x + y + z)^2`
Evaluate of the following:
463+343
Evaluate of the following:
1043 + 963
Evaluate:
483 − 303 − 183
If a2 - 3a + 1 = 0, and a ≠ 0; find:
- `a + 1/a`
- `a^2 + 1/a^2`
Expand the following:
(m + 8) (m - 7)
If `"r" - (1)/"r" = 4`; find : `"r"^4 + (1)/"r"^4`
Simplify:
`("a" - 1/"a")^2 + ("a" + 1/"a")^2`
Which one of the following is a polynomial?
The value of 2492 – 2482 is ______.
