English Medium Class 9 - CBSE Question Bank Solutions for Mathematics

Rationalise the denominator of the following:

`sqrt(40)/sqrt(3)`

Rationalise the denominator of the following:

`16/(sqrt(41) - 5)`

Rationalise the denominator of the following:

`(3 + sqrt(2))/(4sqrt(2))`

Rationalise the denominator of the following:

`(2 + sqrt(3))/(2 - sqrt(3))`

Rationalise the denominator of the following:

`sqrt(6)/(sqrt(2) + sqrt(3))`

Rationalise the denominator of the following:

`(sqrt(3) + sqrt(2))/(sqrt(3) - sqrt(2))`

Rationalise the denominator of the following:

`(3sqrt(5) + sqrt(3))/(sqrt(5) - sqrt(3))`

Rationalise the denominator of the following:

`(4sqrt(3) + 5sqrt(2))/(sqrt(48) + sqrt(18))`

Find the value of a and b in the following:

`(5 + 2sqrt(3))/(7 + 4sqrt(3)) = a - 6sqrt(3)`

Find the value of a and b in the following:

`(3 - sqrt(5))/(3 + 2sqrt(5)) = asqrt(5) - 19/11`

Find the value of a and b in the following:

`(sqrt(2) + sqrt(3))/(3sqrt(2) - 2sqrt(3)) = 2 - bsqrt(6)`

Find the value of a and b in the following:

`(7 + sqrt(5))/(7 - sqrt(5)) - (7 - sqrt(5))/(7 + sqrt(5)) = a + 7/11 sqrt(5)b`

Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.

`4/sqrt(3)`

Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.

`6/sqrt(6)`

Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.

`(sqrt(10) - sqrt(5))/2`

Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.

`sqrt(2)/(2 + sqrt(2)`

Rationalise the denominator in the following and hence evaluate by taking `sqrt(2) = 1.414, sqrt(3) = 1.732` and `sqrt(5) = 2.236`, upto three places of decimal.

`1/(sqrt(3) + sqrt(2))`

Simplify:

`(1/27)^((-2)/3)`

Simplify:

`[((625)^(-1/2))^((-1)/4)]^2`

Simplify:

`64^(-1/3)[64^(1/3) - 64^(2/3)]`