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SSC (English Medium) 10th Standard - Maharashtra State Board Important Questions for Geometry Mathematics 2

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Geometry Mathematics 2
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Prove that sin6θ + cos6θ = 1 – 3 sin2θ. cos2θ.

Appears in 2 question papers
Chapter: [6] Trigonometry
Concept: Trigonometric Identities (Square Relations)

Prove that:

sec2θ + cosec2θ = sec2θ x cosec2θ

Appears in 2 question papers
Chapter: [6] Trigonometry
Concept: Trigonometric Identities (Square Relations)

Eliminate θ, if
x = 3 cosec θ + 4 cot θ
y = 4 cosec θ – 3 cot θ

Appears in 2 question papers
Chapter: [6] Trigonometry
Concept: Trigonometric Identities (Square Relations)

Prove that `(sinθ - cosθ + 1)/(sinθ + cosθ - 1) = 1/(secθ - tanθ)`

Appears in 2 question papers
Chapter: [6] Trigonometry
Concept: Trigonometric Identities (Square Relations)

Four alternative answers for the following question are given. Choose the correct alternative and write its alphabet:

sin θ × cosec θ = ______

Appears in 2 question papers
Chapter: [6] Trigonometry
Concept: Trigonometric Identities (Square Relations)

Prove that `sqrt((1 + sin A)/(1 - sin A))` = sec A + tan A.

Appears in 2 question papers
Chapter: [6] Trigonometry
Concept: Trigonometric Identities (Square Relations)

The radii of the ends of a frustum are 14 cm and 6 cm respectively and its height is 6 cm. Find its curved surface area.

Appears in 2 question papers
Chapter: [7] Mensuration
Concept: Frustum of a Cone

The radius of a circle is 10 cm. The measure of an arc of the circle is 54°. Find the area of the sector associated with the arc. (\[\pi\]= 3.14 )

Appears in 2 question papers
Chapter: [7] Mensuration
Concept: Length of an Arc

In the given figure, square ABCD is inscribed in the sector A - PCQ. The radius of sector C - BXD is 20 cm. Complete the following activity to find the area of shaded region 

Appears in 2 question papers
Chapter: [7] Mensuration
Concept: Length of an Arc

The ratio of the areas of two triangles with the common base is 14 : 9. Height of the larger triangle is 7 cm, then find the corresponding height of the smaller triangle.

Appears in 1 question paper
Chapter: [1] Similarity
Concept: Ratios of Areas of Two Triangles

The ratio of the areas of two triangles with common base is 6:5. Height of the larger triangle of 9 cm, then find the corresponding height of the smaller triangle.

Appears in 1 question paper
Chapter: [1] Similarity
Concept: Ratios of Areas of Two Triangles

Base of a triangle is 9 and height is 5. Base of another triangle is 10 and height is 6. Find the ratio of areas of these triangles.

Appears in 1 question paper
Chapter: [1] Similarity
Concept: Ratios of Areas of Two Triangles

In the given figure, BC ⊥ AB, AD ⊥ AB, BC = 4, AD = 8, then find `("A"(∆"ABC"))/("A"(∆"ADB"))`

Appears in 1 question paper
Chapter: [1] Similarity
Concept: Ratios of Areas of Two Triangles

In adjoining figure, PQ ⊥ BC, AD ⊥ BC then find following ratios.

  1. `("A"(∆"PQB"))/("A"(∆"PBC"))`
  2. `("A"(∆"PBC"))/("A"(∆"ABC"))`
  3. `("A"(∆"ABC"))/("A"(∆"ADC"))`
  4. `("A"(∆"ADC"))/("A"(∆"PQC"))`
Appears in 1 question paper
Chapter: [1] Similarity
Concept: Ratios of Areas of Two Triangles

In ∆PQR, PM = 15, PQ = 25 PR = 20, NR = 8. State whether line NM is parallel to side RQ. Give reason. 

Appears in 1 question paper
Chapter: [1] Similarity
Concept: Property of Three Parallel Lines and Their Transversals

In ∆MNP, NQ is a bisector of ∠N. If MN = 5, PN = 7 MQ = 2.5 then find QP. 

Appears in 1 question paper
Chapter: [1] Similarity
Concept: Property of an Angle Bisector of a Triangle

In trapezium ABCD, side AB || side PQ || side DC, AP = 15, PD = 12, QC = 14, Find BQ. 

Appears in 1 question paper
Chapter: [1] Similarity
Concept: Property of Three Parallel Lines and Their Transversals

Find QP using given information in the figure.

Appears in 1 question paper
Chapter: [1] Similarity
Concept: Property of an Angle Bisector of a Triangle

In the given figure, if AB || CD || FE then find x and AE. 

Appears in 1 question paper
Chapter: [1] Similarity
Concept: Property of an Angle Bisector of a Triangle

 In trapezium PQRS, side PQ || side SR, AR = 5AP, AS = 5AQ then prove that, SR = 5PQ 

 

 

Appears in 1 question paper
Chapter: [1] Similarity
Concept: Ratios of Areas of Two Triangles
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Maharashtra State Board SSC (English Medium) 10th Standard Important Questions
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Important Questions for Maharashtra State Board SSC (English Medium) 10th Standard Marathi (Second Language) [मराठी (द्वितीय भाषा)]
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Important Questions for Maharashtra State Board SSC (English Medium) 10th Standard Sanskrit (Second Language) [संस्कृत (द्वितीय भाषा)]
Important Questions for Maharashtra State Board SSC (English Medium) 10th Standard Sanskrit - Composite [संस्कृत - संयुक्त (द्वितीय भाषा)]
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