English
Maharashtra State BoardSSC (English Medium) 10th Standard

Four alternative answers for the following question are given. Choose the correct alternative and write its alphabet: sin θ × cosec θ = ______

Advertisements
Advertisements

Question

Four alternative answers for the following question are given. Choose the correct alternative and write its alphabet:

sin θ × cosec θ = ______

Options

  • 1

  • 0

  • `1/2`

  • `sqrt2`

MCQ
Fill in the Blanks
Advertisements

Solution

sin θ × cosec θ = 1

Explanation:

sin θ × cosec θ 

= `sintheta xx 1/sinθ   ... [cosec theta = 1/(sintheta)]`

= 1

shaalaa.com
  Is there an error in this question or solution?
2018-2019 (March) Balbharati Model Question Paper Set 3

RELATED QUESTIONS

Prove the following trigonometric identities.

`(cot A - cos A)/(cot A + cos A) = (cosec A - 1)/(cosec A + 1)`


Prove the following trigonometric identities:

tan2 A + cot2 A = sec2 A cosec2 A − 2


If  `sin theta = 1/2 , " write the value of" ( 3 cot^2 theta + 3).`


Find the value of sin ` 48° sec 42° + cos 48°  cosec 42°`

 


What is the value of \[\sin^2 \theta + \frac{1}{1 + \tan^2 \theta}\]


 Write True' or False' and justify your answer  the following : 

The value of  \[\cos^2 23 - \sin^2 67\]  is positive . 


If cos A + cos2 A = 1, then sin2 A + sin4 A =


Prove the following identity :

tanA+cotA=secAcosecA 


Prove the following identity :

`cos^4A - sin^4A = 2cos^2A - 1`


Without using trigonometric table , evaluate : 

`cos90^circ + sin30^circ tan45^circ cos^2 45^circ`


Prove that sec θ. cosec (90° - θ) - tan θ. cot( 90° - θ ) = 1.


Prove that `(sin (90° - θ))/cos θ + (tan (90° - θ))/cot θ + (cosec (90° - θ))/sec θ = 3`.


Without using the trigonometric table, prove that
tan 10° tan 15° tan 75° tan 80° = 1


Prove that: `cos^2 A + 1/(1 + cot^2 A) = 1`.


Prove that : `tan"A"/(1 - cot"A") + cot"A"/(1 - tan"A") = sec"A".cosec"A" + 1`.


Prove the following identities.

sec6 θ = tan6 θ + 3 tan2 θ sec2 θ + 1


If `tan θ = 9/40`, complete the activity to find the value of sec θ.

Activity:

sec2θ = 1 + `square`   ...[Fundamental trigonometric identity]

sec2θ = 1 + `square^2`

sec2θ = 1 + `square` 

sec θ = `square` 


Prove that sec2θ – cos2θ = tan2θ + sin2θ.


Prove that sec2θ – cos2θ = tan2θ + sin2θ.


The value of tan A + sin A = M and tan A - sin A = N.

The value of `("M"^2 - "N"^2) /("MN")^0.5`


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×