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Maharashtra State BoardSSC (English Medium) 10th Standard

The radii of the ends of a frustum are 14 cm and 6 cm respectively and its height is 6 cm. Find its curved surface area. - Geometry Mathematics 2

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Question

The radii of the ends of a frustum are 14 cm and 6 cm respectively and its height is 6 cm. Find its curved surface area.

Sum
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Solution

Given: Radii (r1) = 14 cm, r2 = 6 cm, height (h) = 6 cm

Slant height of the frustum (l)

= `sqrt(h^2 + (r_1 - r_2)^2)`

= `sqrt(6^2 + (14 - 6)^2)`

= `sqrt(6^2 + 8^2)`

= `sqrt(36 + 64)`

= `sqrt(100)`

= 10 cm

Curved surface area of the frustum 

= πl (r1 + r2)

= 3.14 × 10 (14 + 6)

= 3.14 × 10 × 20

= 628 cm2

∴ The curved surface area of the frustum is 628 cm2.

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Chapter 7: Mensuration - Practice set 7.2 [Page 148]

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