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A Container, Open at the Top, is in the Form of a Frustum of a Cone of Height 24 Cm with Radii of Its Lower and Upper Circular Ends as 8 Cm and 20 Cm, Respectively. Find the Cost - Mathematics

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Question

A container, open at the top, is in the form of a frustum of a cone of height 24 cm with radii of its lower and upper circular ends as 8 cm and 20 cm, respectively. Find the cost of milk which can completely fill the container at the rate of ₹21 per litre.

Sum
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Solution

We have,

Height, h = 24 cm,

Upper radius, R = 20 cm ad 

Lower radius, R =  8 cm

Now,

A container, open at the top, is in the form of a frustum of a cone of height 24 cm with radii of its lower and upper circular ends as 8 cm and 20 cm, respectively. Find the cost of milk which can completely fill the container at the rate of ₹21 per litre.

Volume of the the container `= 1/3pi"h"("R"^2+r^2+Rr)`

`= 1/3 xx 22/7xx24xx(20^2 + 8^2 +20xx8)`

`= 176/7xx(400+64+160)`

`=176/7xx624`

`=109824/7 "cm"^3`

`= 109824/7  "L"`        (As, 1000 Cm3 = 1 L)

So, the cost of the millk in the  container `= 109.824/7 xx 21`= 329.4712

≈ ₹ 329.47

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Chapter 19: Volume and Surface Area of Solids - Exercise 19C [Page 911]

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R.S. Aggarwal Mathematics [English] Class 10
Chapter 19 Volume and Surface Area of Solids
Exercise 19C | Q 4 | Page 911
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