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Science (English Medium) Class 12 - CBSE Important Questions for Mathematics

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Find the vector and Cartesian equations of the line through the point (1, 2, −4) and perpendicular to the two lines. 

`vecr=(8hati-19hatj+10hatk)+lambda(3hati-16hatj+7hatk) " and "vecr=(15hati+29hatj+5hatk)+mu(3hati+8hatj-5hatk)`

 

 

Appears in 3 question papers
Chapter: [11] Three - Dimensional Geometry
Concept: Equation of a Line in Space

Find the distance between the point (−1, −5, −10) and the point of intersection of the line `(x-2)/3=(y+1)/4=(z-2)/12` and the plane x-y+z=5

Appears in 3 question papers
Chapter: [11] Three - Dimensional Geometry
Concept: Three - Dimensional Geometry Examples and Solutions

If lines `(x−1)/2=(y+1)/3=(z−1)/4 and  (x−3)/1=(y−k)/2=z/1` intersect, then find the value of k and hence find the equation of the plane containing these lines.

Appears in 3 question papers
Chapter: [11] Three - Dimensional Geometry
Concept: Three - Dimensional Geometry Examples and Solutions

If the Cartesian equations of a line are ` (3-x)/5=(y+4)/7=(2z-6)/4` , write the vector equation for the line.

Appears in 3 question papers
Chapter: [11] Three - Dimensional Geometry
Concept: Equation of a Line in Space

Find the equation of the plane through the line of intersection of the planes x + y + z = 1 and 2x + 3y + 4z = 5 which is perpendicular to the plane x − y + z = 0. Also find the distance of the plane, obtained above, from the origin.

Appears in 3 question papers
Chapter: [11] Three - Dimensional Geometry
Concept: Distance of a Point from a Plane

Find the equation of the plane through the line of intersection of the planes x + y + z = 1 and 2x + 3y + 4z = 5 which is perpendicular to the plane x − y + z = 0. Also find the distance of the plane, obtained above, from the origin.

Appears in 3 question papers
Chapter: [11] Three - Dimensional Geometry
Concept: Distance of a Point from a Plane

Find the distance of the point (2, 12, 5) from the point of intersection of the line 

`vecr=2hati-4hat+2hatk+lambda(3hati+4hatj+2hatk) `

Appears in 3 question papers
Chapter: [11] Three - Dimensional Geometry
Concept: Three - Dimensional Geometry Examples and Solutions

Find the equation of the plane through the line of intersection of `vecr*(2hati-3hatj + 4hatk) = 1`and `vecr*(veci - hatj) + 4 =0`and perpendicular to the plane `vecr*(2hati - hatj + hatk) + 8 = 0`. Hence find whether the plane thus obtained contains the line x − 1 = 2y − 4 = 3z − 12.

Appears in 3 question papers
Chapter: [11] Three - Dimensional Geometry
Concept: Vector and Cartesian Equation of a Plane

Find the vector and Cartesian equations of a line passing through (1, 2, –4) and perpendicular to the two lines `(x - 8)/3 = (y + 19)/(-16) = (z - 10)/7` and `(x - 15)/3 = (y - 29)/8 = (z - 5)/(-5)`

Appears in 3 question papers
Chapter: [11] Three - Dimensional Geometry
Concept: Equation of a Line in Space

If a line makes angles α, β and γ with the coordinate axes, find the value of cos2α + cos2β + cos2γ.

Appears in 3 question papers
Chapter: [11] Three - Dimensional Geometry
Concept: Direction Cosines and Direction Ratios of a Line

Read the following passage and answer the questions given below.

Two motorcycles A and B are running at the speed more than the allowed speed on the roads represented by the lines `vecr = λ(hati + 2hatj - hatk)` and `vecr = (3hati + 3hatj) + μ(2hati + hatj + hatk)` respectively.

Based on the above information, answer the following questions:

  1. Find the shortest distance between the given lines.
  2. Find the point at which the motorcycles may collide.
Appears in 3 question papers
Chapter: [11] Three - Dimensional Geometry
Concept: Shortest Distance Between Two Lines

If the distance of the point (1, 1, 1) from the plane x – y + z + λ = 0 is `5/sqrt(3)`, find the value(s) of λ.

Appears in 3 question papers
Chapter: [11] Three - Dimensional Geometry
Concept: Distance of a Point from a Plane

If the distance of the point (1, 1, 1) from the plane x – y + z + λ = 0 is `5/sqrt(3)`, find the value(s) of λ.

Appears in 3 question papers
Chapter: [11] Three - Dimensional Geometry
Concept: Distance of a Point from a Plane

Equation of a line passing through (1, 1, 1) and parallel to z-axis is ______.

Appears in 3 question papers
Chapter: [11] Three - Dimensional Geometry
Concept: Equation of a Line in Space

Find the coordinates of points on line `x/1 = (y - 1)/2 = (z + 1)/2` which are at a distance of `sqrt(11)` units from origin.

Appears in 3 question papers
Chapter: [11] Three - Dimensional Geometry
Concept: Distance of a Point from a Plane

Find the coordinates of points on line `x/1 = (y - 1)/2 = (z + 1)/2` which are at a distance of `sqrt(11)` units from origin.

Appears in 3 question papers
Chapter: [11] Three - Dimensional Geometry
Concept: Distance of a Point from a Plane

If a line makes angles of 90°, 135° and 45° with the x, y and z axes respectively, then its direction cosines are ______.

Appears in 3 question papers
Chapter: [11] Three - Dimensional Geometry
Concept: Direction Cosines and Direction Ratios of a Line

The angle between the lines 2x = 3y = – z and 6x = – y = – 4z is ______.

Appears in 3 question papers
Chapter: [11] Three - Dimensional Geometry
Concept: Angle Between Two Lines

Find the distance between the lines:

`vecr = (hati + 2hatj - 4hatk) + λ(2hati + 3hatj + 6hatk)`;

`vecr = (3hati + 3hatj - 5hatk) + μ(4hati + 6hatj + 12hatk)`

Appears in 3 question papers
Chapter: [11] Three - Dimensional Geometry
Concept: Shortest Distance Between Two Lines

A dealer in rural area wishes to purchase a number of sewing machines. He has only Rs 5,760 to invest and has space for at most 20 items for storage. An electronic sewing machine cost him Rs 360 and a manually operated sewing machine Rs 240. He can sell an electronic sewing machine at a profit of Rs 22 and a manually operated sewing machine at a profit of Rs 18. Assuming that he can sell all the items that he can buy, how should he invest his money in order to maximize his profit? Make it as a LPP and solve it graphically.

Appears in 3 question papers
Chapter: [12] Linear Programming
Concept: Graphical Method of Solving Linear Programming Problems
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