Definitions [5]
The median is the middle value of an arranged data set. It divides the data into two equal parts: 50% of observations lie below it and 50% lie above it.
In a grouped frequency distribution, the modal class is the class interval that has the highest frequency.
A histogram is a graphical representation of a continuous grouped frequency distribution using adjacent rectangles. Class intervals are marked on the horizontal axis, while frequency or frequency density is marked on the vertical axis.
A graph formed by plotting class marks against their corresponding frequencies and joining consecutive points with straight line segments is called a frequency polygon.
A circular diagram divided into sectors whose angles are proportional to the corresponding data values is called a pie diagram or pie chart.
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The complete circle represents the total value and measures 360°.
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Each sector represents one component of the total.
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A larger component produces a larger sector.
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Equal components produce equal sectors.
Formulae [5]
\[ \begin{array}{c} \text{The mean of statistical data} = \dfrac{\text{The sum of all scores}}{\text{Total no. of scores}} = \dfrac{\sum\limits_{i = 1}^{N} x_{i}}{N} \end{array} \]
(Here \[ x_{i} \] is the \[ i^{th} \] score)
Mean is denoted by \[ \overline{X} \] and it represents the average of the given data.
\[ \overline{X} = \frac{\sum\limits_{i = 1}^{N} x_{i}}{N} \]
If n is odd:
Median =\[\left(\frac{n+1}{2}\right)\]th observation
If n is even:
\[ \text{Median} = \frac{\left(\frac{n}{2}\right) \text{th observation} + \left(\frac{n}{2} + 1\right) \text{th observation}}{2} \]
\[\mathrm{Median}=l+\frac{\left(\frac{n}{2}-cf\right)}{f}\times h\]
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l = lower limit of median class
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n = total frequency
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cf = cumulative frequency of class before median class
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f = frequency of median class
Classes must be continuous before applying the median formula.
\[\mathrm{Mode}=l+\left(\frac{f_1-f_0}{2f_1-f_0-f_2}\right)\times h\]
l = lower limit of the modal class,
h = size of the class interval (assuming all class sizes to be equal),
f1 = frequency of the modal class,
f0 = frequency of the class preceding the modal class,
f2 = frequency of the class succeeding the modal class.
\[\text{Central angle}=\frac{\text{Value of component}}{\text{Total value}}\times360^\circ\]
Symbol Form
Let:
\[ x \] = component value
\[ T \] = total value, where \[ T > 0 \]
\[ \theta \] = central angle
Then:
\[ \theta = \frac{x}{T} \times 360^{\circ} \]
Key Points
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Statistics deals with collecting, organising, analysing, and interpreting data.
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Central tendency gives a single representative value for a data set.
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Mean is the arithmetic average.
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Median is the middle value of ordered data.
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Mode is the most frequently occurring value.
- Grouped data uses class intervals.
- Class mark \[ x_{i} = \frac{\text{lower limit} + \text{upper limit}}{2}. \]
- Direct method: \[ \bar{x} = \frac{\sum f_{i}x_{i}}{N}. \]
- Assumed mean method: \[ \bar{x} = A + \frac{\sum f_{i}d_{i}}{N}. \]
- Step-deviation method: \[ \bar{x} = A + \left(\frac{\sum f_{i}u_{i}}{N}\right)g. \]
- \[ d_{i} = x_{i} - A, \; u_{i} = \frac{d_{i}}{g}, \; N = \sum f_{i}. \]
- The mean of grouped data is an estimate.
- Always show the calculation table and mention units in board answers.
- The median divides arranged data into two equal parts.
- For ungrouped data:
Odd \[ n: \] median is the \[ \left(\frac{n + 1}{2}\right) \text{th value.} \]
Even \[ n: \] median is the average of the \[ \frac{n}{2} \text{th} \] and \[ \left(\frac{n}{2} + 1\right) \text{th values.} \] - For grouped data, first prepare a cumulative-frequency table.
- The median class is the class where cumulative frequency first becomes greater than or equal to \[ n/2. \]
- Convert inclusive classes into continuous classes before applying the formula.
- Use: \[ \boxed{\text{Median} = l + \frac{\left(\frac{n}{2} - cf\right)}{f} \times h} \]
- The median is preferred when data contains extreme values.
Mode = most frequently occurring value.
For grouped data, first find the modal class.
Modal class = class interval with the highest frequency.
Formula:
\[ \text{Mode} = l + \left(\frac{f_{1} - f_{0}}{2f_{1} - f_{0} - f_{2}}\right)h \]
- A table organises exact data; a graph makes patterns easier to notice.
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A bar diagram is used for the comparison of quantities.
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A pie diagram shows data in percentage or proportional form.
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A line graph shows change over time.
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A histogram is used for a grouped frequency distribution.
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A frequency polygon represents a frequency distribution graphically.
- A Histogram is a graphical representation of a grouped frequency distribution using rectangles.
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It is used for continuous grouped data.
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Class intervals are shown on the X-axis.
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Frequencies are shown on the Y-axis.
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Rectangles are drawn without gaps between them.
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The height of each rectangle is proportional to its frequency.
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A frequency polygon is a graph obtained by joining the points
(class-mark, frequency) by straight line segments. -
Class-mark = midpoint of the class interval.
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Two imagined classes (with zero frequency) are taken at the beginning and end to close the polygon.
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A frequency polygon is drawn on the same axes as the histogram (if a histogram is given).
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The polygon starts and ends on the x-axis.
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A pie diagram represents data using a circle.
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The whole circle = total data = 360°.
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Each part of the data is shown by a sector.
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The central angle of a sector is proportional to the data value.
- Larger value → larger sector, smaller value → smaller sector.
Important Questions [17]
- The following table shows the classification of percentage of marks of students and the number of students. Draw frequency polygon from the table without drawing histogram: Result (Percentage) 20 - 40
- Draw the Frequency Polygon for the Following Frequency Distribution
- Given Below is the Frequency Distribution of Driving Speeds (In Km/Hour) of The Vehicles of 400 College Students
- Represent the Following Data by Histogram
- The following is the frequency distribution of waiting time at ATM centre; draw histogram to represent the data
- Draw Histogram and Frequency Polygon on the Same Graph Paper for the Following Frequency Distribution
- Draw a histogram of the following data. Height of Student (Cm) 135 - 140, 140 - 145, 145 - 150, 150 - 155 No. of Students 4, 12, 16, 8
- The following frequency distribution table shows marks obtained by 180 students in Mathematics examination. Marks 0 - 10, 10 - 20, 20 - 30, 30 - 40, 40 - 50 No. of students 25, x, 30, 2x, 65
- Represent the Following Data by Histogram:
- Draw Histogram and Hence the Frequency Polygon for the Following Frequency Distribution:
- Show the following data by a frequency polygon: Electricity bill (₹) Families 200 – 400 240 400 – 600 300 600 – 800 450 800 – 1000 350 1000 – 1200 160
- The Marks Scored by Students in Mathematics in a Certain Examination Are Given Below
- Draw the Histogram and Hence, the Frequency Polygon for the Following Frequency Distribution:
- The Marks Scored by Students in Mathematics in a Certain Examination Are Given Below :Draw Histogram for the Above Data.
- Represent the following data by histogram: Price of Sugar (per kg in ₹) Number of Weeks 18 – 20 4 20 – 22 8 22 – 24 22 24 – 26 12 26 – 28 6 28 – 30 8
- The Maximum Bowing Speed (Km/Hour) Or 33 Players at a Cricket Coaching Centre is Given Below:
- The Time Required for Some Students to Complete a Science Experiment and the Number of Students is Shown in the Following Grouped Frequency Distribution Table.
