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Write the Vector Equation of a Line Given by X − 5 3 = Y + 4 7 = Z − 6 2 . - Mathematics

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Question

Write the vector equation of a line given by \[\frac{x - 5}{3} = \frac{y + 4}{7} = \frac{z - 6}{2} .\]

 

Short/Brief Note
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Solution

We have ,

\[\frac{x - 5}{3} = \frac{y + 4}{7} = \frac{z - 6}{2} .\]

The given line passes through the point (5, - 4 , 6 ) and has direction ratios proportional to 3, 7, 2.
Vector equation of the given line passing through the point having position vector

\[\overrightarrow{a} = 5 \hat{i} - 4 \hat{j} + 6 \hat{k} \] and parallel to a vector  \[\overrightarrow{b} = 3 \hat{i} + 7 \hat{j} + 2 \hat{k} \]  is  \[\overrightarrow{r} = \overrightarrow{a} + \lambda \overrightarrow{b} \]

\[ \Rightarrow \overrightarrow{r} = 5 \hat{i}  - 4 \hat{j}  + 6 \hat{k} + \lambda\left( 3 \hat{i}  + 7 \hat{j}  + 2 \hat{k}  \right)\]

 

 

 

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Chapter 28: Straight Line in Space - Very Short Answers [Page 41]

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RD Sharma Mathematics [English] Class 12
Chapter 28 Straight Line in Space
Very Short Answers | Q 17 | Page 41

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