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Question
Without expanding the determinant, find the value of `|(10, 57, 107),(12, 64, 124),(15, 78, 153)|`.
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Solution
Let D = `|(10, 57, 107),(12, 64, 124),(15, 78, 153)|`
Applying C3 → C3 – C2, we get
D = `|(10, 57, 50),(12, 64, 60),(15, 78, 75)|`
Taking (5) common from C3, we get
D = `5|(10, 57, 10),(12, 64, 12),(15, 78, 15)|`
= 5(0) ...[∵ C1 and C3 are identical]
= 0
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