English
Karnataka Board PUCPUC Science 2nd PUC Class 12

Why in the redox titration of KMnOX4 vs oxalic acid, we heat oxalic acid solution before starting the titration?

Advertisements
Advertisements

Question

Why in the redox titration of \[\ce{KMnO4}\] vs oxalic acid, we heat oxalic acid solution before starting the titration?

Short/Brief Note
Advertisements

Solution

The reaction between \[\ce{KMnO4}\] and oxalic acid is very slow. By raising the temperature we can increase the rate of reaction.

shaalaa.com
  Is there an error in this question or solution?
Chapter 4: Chemical Kinetics - Exercises [Page 56]

APPEARS IN

NCERT Exemplar Chemistry Exemplar [English] Class 12
Chapter 4 Chemical Kinetics
Exercises | Q III. 49. | Page 56

RELATED QUESTIONS

Explain a graphical method to determine activation energy of a reaction.


 

Consider the reaction

`3I_((aq))^-) +S_2O_8^(2-)->I_(3(aq))^-) + 2S_2O_4^(2-)`

At particular time t, `(d[SO_4^(2-)])/dt=2.2xx10^(-2)"M/s"`

What are the values of the following at the same time?

a. `-(d[I^-])/dt`

b. `-(d[S_2O_8^(2-)])/dt`

c. `-(d[I_3^-])/dt`

 

 

What will be the effect of temperature on rate constant?


The rate of the chemical reaction doubles for an increase of 10 K in absolute temperature from 298 K. Calculate Ea.


The rate constant for the decomposition of N2O5 at various temperatures is given below:

T/°C 0 20 40 60 80
105 × k/s−1 0.0787 1.70 25.7 178 2140

Draw a graph between ln k and `1/T` and calculate the values of A and Ea. Predict the rate constant at 30º and 50ºC.


The rate constant for the decomposition of hydrocarbons is 2.418 × 10−5 s−1 at 546 K. If the energy of activation is 179.9 kJ/mol, what will be the value of pre-exponential factor?


The rate of a reaction quadruples when the temperature changes from 293 K to 313 K. Calculate the energy of activation of the reaction assuming that it does not change with temperature.


In the Arrhenius equation for a first order reaction, the values of ‘A’ of ‘Ea’ are 4 × 1013 sec−1 and 98.6 kJ mol1 respectively. At what temperature will its half life period be 10 minutes?

[R = 8.314 J K1 mol1]


The rate constant of a first order reaction are 0.58 S-1 at 313 K and 0.045 S-1 at 293 K. What is the energy of activation for the reaction?


Define activation energy.


What is the effect of adding a catalyst on Activation energy (Ea)


 Write a condition under which a bimolecular reaction is kinetically first order. Give an example of  such a reaction. (Given : log2 = 0.3010,log 3 = 0.4771, log5 = 0.6990).


 Predict the main product of the following reactions:


The rate of chemical reaction becomes double for every 10° rise in temperature because of ____________.


Activation energy of a chemical reaction can be determined by ______.


Which of the following graphs represents exothermic reaction?

(a)  

(b)  

(c)  


Oxygen is available in plenty in air yet fuels do not burn by themselves at room temperature. Explain.


The activation energy of one of the reactions in a biochemical process is 532611 J mol–1. When the temperature falls from 310 K to 300 K, the change in rate constant observed is k300 = x × 10–3 k310. The value of x is ______.

[Given: ln 10 = 2.3, R = 8.3 J K–1 mol–1]


A schematic plot of ln Keq versus inverse of temperature for a reaction is shown below

The reaction must be:


What happens to the rate constant k and activation energy Ea as the temperature of a chemical reaction is increased? Justify.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×