Advertisements
Advertisements
Question
Why dextro and laevorotatory isomers of Butan-2-ol are difficult to separate by fractional distillation?
Advertisements
Solution
Dextro and laevorotatory isomers of Butan-2-ol are enantiomers of each other and both have the same boiling point and hence they cannot be separated by fractional distillation.
APPEARS IN
RELATED QUESTIONS
Define racemic mixture.
For the same alkyl group, an alkyl bromide has a higher boiling point than alkyl fluoride because:
Which of the following halide is 2°?
The decreasing order of boiling points of alkyl halides is:
Which of the following possesses the highest melting point?
Out of o-and p-dibromobenzene which one has higher melting point and why?
Assertion: The boiling points of alkyl halides decrease in the order:
RI > RBr > RCl > RF
Reason: The boiling points of alkyl chlorides, bromides and iodides are considerably higher than that of the hydrocarbon of comparable molecular mass.
Arrange the following compounds in increasing order of their boiling points:
CH3CH2OH, CH3−CHO, CH3−COOH
Arrange the isomeric dichlorobenzene in the increasing order of their boiling point and melting points.
Write the structure of the following organic halogen compound.
4-tert-Butyl-3-iodoheptane
