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प्रश्न
Why dextro and laevorotatory isomers of Butan-2-ol are difficult to separate by fractional distillation?
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उत्तर
Dextro and laevorotatory isomers of Butan-2-ol are enantiomers of each other and both have the same boiling point and hence they cannot be separated by fractional distillation.
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संबंधित प्रश्न
Give reasons : n-Butyl bromide has higher boiling point than t-butyl bromide.
Which of the following compounds has the highest boiling point?
The decreasing order of boiling points of alkyl halides is:
Which of the following possesses the highest melting point?
Arrange the following compounds in increasing order of their boiling points.
(a) \[\begin{array}{cc}
\ce{CH3}\phantom{..................}\\
\backslash\phantom{...........}\\
\ce{CH - CH - CH2Br}\\
/\phantom{.............}\\
\ce{CH3}\phantom{..................}
\end{array}\]
(b) \[\ce{CH3CH2CH2CH2Br}\]
(c) \[\begin{array}{cc}
\phantom{...}\ce{CH3}\\
\phantom{}|\\
\ce{H3C - C - CH3}\\
\phantom{}|\\
\phantom{..}\ce{Br}
\end{array}\]
Which of the following compounds will have the highest melting point and why?
| (I) |  |
|
(II) |
 |
| (III) |  |
Write the structure of the following organic halogen compound.
1,4-Dibromobut-2-ene
Write the structure of the following organic halogen compound.
4-tert-Butyl-3-iodoheptane
Write the structure of the following organic halogen compound:
4-tert-Butyl-3-iodoheptane
Write the structure of the following organic halogen compound.
4-tert-Butyl-3-iodoheptane
