Advertisements
Advertisements
Question
What would you observe in the following case:
Sugar crystals are added to a hard glass test tube containing concentrated sulphuric acid.
Advertisements
Solution
Charring of sugar takes place. Sulphuric acid dehydrates sugar, leaving behind carbon, which is black. Black charred residue is observed.
\[\ce{C12H22O11 ->[Conc. H2SO4] \underset{Black charred residue}{12 C + 11H2O}}\]
APPEARS IN
RELATED QUESTIONS
Give one equation to show the following properties of sulphuric acid:
As a non-volatile acid
Name the following :
The precipitate obtained by treating aqueous lead nitrate with dilute sulphuric acid.
Write balanced equation for the reaction of dilute sulphuric acid with the following:
Copper carbonate
Write balanced equation for the reaction of dilute sulphuric acid with the following:
Zinc hydroxide
- Name the catalyst which helps in the conversion of sulphur dioxide to sulphur trioxide in step C.
- In the contact process for the manufacture of sulphuric acid, sulphur trioxide is not converted to sulphuric acid by reacting it with water. Instead a two-step procedure is used. Write the equations for the two steps involved in D.
- What type of substance will liberate sulphur dioxide from sodium sulphite in step E?
- Write the equation for the reaction by which sulphur dioxide is converted to sodium sulphite in step F.
State your observation for the following case:
Paper soaked in potassium permanganate solution is introduced into a gas jar of sulphur dioxide.
State one appropriate observation of the following:
Concentrated sulphuric acid is added dropwise to a crystal of hydrated copper sulphate.
Write the balanced chemical equation for the following conversion:
Ammonium sulphate from ammonia and dilute sulphuric acid.
Dilute hydrochloric acid and dilute sulphuric acid are both colourless solutions. How will the addition of barium chloride solution to each help to distinguish between the two?
Write the observation for the following:
Decomposition of bicarbonates by dil. H2SO4.
\[\ce{2NaHCO3 + H2SO4 -> Na2SO4 + 2H2O + 2CO2}\]
