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प्रश्न
What would you observe in the following case:
Sugar crystals are added to a hard glass test tube containing concentrated sulphuric acid.
State your observation when sugar crystals are added to a hard glass test tube containing conc. sulphuric acid.
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उत्तर
Charring of sugar takes place. Sulphuric acid dehydrates sugar, leaving behind carbon, which is black. Black charred residue is observed.
\[\ce{C12H22O11 ->[Conc. H2SO4] \underset{Black charred residue}{12 C + 11H2O}}\]
संबंधित प्रश्न
Give one equation to show the following properties of sulphuric acid:
Dehydrating property
Name the products formed when hot and concentrated sulphuric acid reacts with Sulphur.
Give main difference between drying agent and dehydrating agent.
Choose the current answer from the options given below :
When conc. H2SO4 comes in contact with sugar, it becomes black due to
Name the catalyst used in the process.
Write balanced equation for the reaction of dilute sulphuric acid with the following:
Zinc hydroxide
Give one equation to show the following property of sulphuric acid:
Acidic nature
Write balanced chemical equation to show :
The oxidizing action of conc.sulphuric acid on carbon
Write the balanced chemical equation for the following conversion:
Copper sulphate from copper and concentrated sulphuric acid.
Complete the table given below:
| Name of the process | Reactants | Acid product formed |
| (a) ______ | Nitrogen dioxide + water + oxygen | (b) ______ |
| (c) ______ | Oleum + water | Sulphuric acid |
