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प्रश्न
What would you observe in the following case:
Sugar crystals are added to a hard glass test tube containing concentrated sulphuric acid.
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उत्तर
Charring of sugar takes place. Sulphuric acid dehydrates sugar, leaving behind carbon, which is black. Black charred residue is observed.
\[\ce{C12H22O11 ->[Conc. H2SO4] \underset{Black charred residue}{12 C + 11H2O}}\]
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संबंधित प्रश्न
How will you distinguish between dilute hydrochloric acid and dilute sulphuric acid using lead nitrate solution?
State your observations when Concentrated Sulphuric acid is added to Sugar Crystals
Distinguish between the given pairs of compounds using the test given within brackets:
Dilute sulphuric acid and dilute hydrochloric acid (using barium chloride solution)
Name the products formed when hot and concentrated sulphuric acid reacts with NaOH.
Choose the current answer from the options given below :
When conc. H2SO4 comes in contact with sugar, it becomes black due to
What do you observe when barium chloride solution is added to dilute sulphuric acid ?
Name the gas evolved in following case:
The gas produced by the action of concentrated sulphuric acid on sodium chloride.
Give one equation to show the following property of sulphuric acid:
Acidic nature
Write balanced chemical equation to show :
The dehydrating property of conc.sulphuric acid
Name the gas released when sodium carbonate is added to a solution of sulphur dioxide.
