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प्रश्न

- Name the catalyst which helps in the conversion of sulphur dioxide to sulphur trioxide in step C.
- In the contact process for the manufacture of sulphuric acid, sulphur trioxide is not converted to sulphuric acid by reacting it with water. Instead a two-step procedure is used. Write the equations for the two steps involved in D.
- What type of substance will liberate sulphur dioxide from sodium sulphite in step E?
- Write the equation for the reaction by which sulphur dioxide is converted to sodium sulphite in step F.
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उत्तर
- Platinum or Vanadium pentoxide
- \[\ce{SO3 + H2SO4 -> H2S2O7}\]
- \[\ce{H2S2O7 + H2O -> 2H2SO4}\]
- The substance that will liberate sulphur dioxide in step E is dilute sulphuric acid (H2SO4).
- \[\ce{SO2 + 2NaOH -> Na2SO3 + H2O}\]
- \[\ce{Na2O + SO2 -> Na2SO3}\]
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संबंधित प्रश्न
Give a chemical test to distinguish between dilute sulphuric acid and conc. sulphuric acid.
Why is concentrated sulphuric acid kept in air tight bottles?
Define the following term : Hygroscopic substance
What would you see, when a crystal of CuSO4.5H2O is placed in concentrated sulphuric acid? Give reason to explain your observation.
Write the equation for the laboratory preparation of the following salts, using sulphuric acid.
Iron (II) sulphate from iron.
Write the observation for the following:
Decomposition of bicarbonates by dil. H2SO4.
\[\ce{2NaHCO3 + H2SO4 -> Na2SO4 + 2H2O + 2CO2}\]
State your observation of the following case:
When dilute hydrochloric acid is added to sodium carbonate crystals.
Give balanced chemical equation to prepare the following salt:
Sodium sulphate using dilute sulphuric acid
Identify the gas evolved and give the chemical test in the following case:
Dilute hydrochloric acid reacts with sodium sulphite.
An acid obtained from concentrated nitric acid on reaction with Sulphur ______.
