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प्रश्न

- Name the catalyst which helps in the conversion of sulphur dioxide to sulphur trioxide in step C.
- In the contact process for the manufacture of sulphuric acid, sulphur trioxide is not converted to sulphuric acid by reacting it with water. Instead a two-step procedure is used. Write the equations for the two steps involved in D.
- What type of substance will liberate sulphur dioxide from sodium sulphite in step E?
- Write the equation for the reaction by which sulphur dioxide is converted to sodium sulphite in step F.
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उत्तर
- Platinum or Vanadium pentoxide
- \[\ce{SO3 + H2SO4 -> H2S2O7}\]
- \[\ce{H2S2O7 + H2O -> 2H2SO4}\]
- The substance that will liberate sulphur dioxide in step E is dilute sulphuric acid (H2SO4).
- \[\ce{SO2 + 2NaOH -> Na2SO3 + H2O}\]
- \[\ce{Na2O + SO2 -> Na2SO3}\]
संबंधित प्रश्न
Give one equation to show the following properties of sulphuric acid:
Dehydrating property
Name the products formed when hot and concentrated sulphuric acid reacts with Sulphur.
Name the products formed when hot and concentrated sulphuric acid reacts with NaOH.
Name the following :
The precipitate obtained by treating aqueous lead nitrate with dilute sulphuric acid.
What would you observe in the following case?
Dilute sulphuric acid is added to ferrous sulphate solution.
Give reason for the following:
When concentrated sulphuric acid is added to blue crystalline copper sulphate, it turns powdery white.
Write the equation of the following reaction:
Sulphur is heated with concentrated sulphuric acid.
Write balanced chemical equation to show :
The behavior of H2SO4 as an acid when it reacts with magnesium.
Write balanced chemical equation to show :
The dehydrating property of conc. sulphuric acid
Concentrated sulphuric acid is both an oxidizing agent and a non-volatile acid. Write one equation each to illustrate the properties of sulphuric acid mentioned above.
