Advertisements
Advertisements
Question
What vertical height of water will exert a pressure of 333200 Pa? The density of water is 1000 kgnr3 and g = 9.8 ms−2.
Advertisements
Solution
Vertical height of water = h =?
Pressure due to water column = P = 333200 Pa Acceleration due to gravity = g = 9.8 ms−2 = 9.8 ms−2
P = hρg
h = P/ρg
h = `333200/(1000xx9.8)`
h = 34 m
APPEARS IN
RELATED QUESTIONS
What is the pressure exerted by 75 cm vertical column of mercury of density 13600 kgm−3 in SI units?
[Take g = 9.8 ms−2].
Calculate the equivalent height of mercury, which will exert as much pressure as 960 m of seawater of density 1040 kgm−3. The density of mercury is 13600 kgm−3.
The pressure of water on the ground floor, in a water pipe is 150000 Pa, whereas pressure on the fourth floor is 30000 Pa. Calculate the height of the fourth floor. Take g = 10 ms−2.
The pressure of water on the ground floor is 160000 Pa. Calculate the pressure on the fifth floor, at a height of 15 m.
What fact about liquid pressure does the following diagram in the following figure illustrate?
What is the SI unit of density?
What do you mean by relative density?
