Advertisements
Advertisements
Question
What vertical height of water will exert a pressure of 333200 Pa? The density of water is 1000 kgnr3 and g = 9.8 ms−2.
Advertisements
Solution
Vertical height of water = h =?
Pressure due to water column = P = 333200 Pa Acceleration due to gravity = g = 9.8 ms−2 = 9.8 ms−2
P = hρg
h = P/ρg
h = `333200/(1000xx9.8)`
h = 34 m
APPEARS IN
RELATED QUESTIONS
What is the pressure exerted by 75 cm vertical column of mercury of density 13600 kgm−3 in SI units?
[Take g = 9.8 ms−2].
Pressure at the bottom of the sea at some particular place is 8968960 Pa. If the density of seawater is 1040 kgm3 calculate the depth of the sea. Take g = 9.8 ms−2. Neglect the pressure of the atmosphere.
Calculate the equivalent height of mercury, which will exert as much pressure as 960 m of seawater of density 1040 kgm−3. The density of mercury is 13600 kgm−3.
The pressure of water on the ground floor, in a water pipe is 150000 Pa, whereas pressure on the fourth floor is 30000 Pa. Calculate the height of the fourth floor. Take g = 10 ms−2.
What fact about liquid pressure does the following diagram in the following figure illustrate?
What is the SI unit of density?
