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प्रश्न
What vertical height of water will exert a pressure of 333200 Pa? The density of water is 1000 kgnr3 and g = 9.8 ms−2.
संख्यात्मक
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उत्तर
Vertical height of water = h =?
Pressure due to water column = P = 333200 Pa Acceleration due to gravity = g = 9.8 ms−2 = 9.8 ms−2
P = hρg
h = P/ρg
h = `333200/(1000xx9.8)`
h = 34 m
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