Advertisements
Advertisements
Question
(i) Calculate the height of a water column which will exert on its base the same
Pressure as the 70 cm column of mercury.
(ii) Will the height of the water column change if the cross-section of the water column is made wider?
Advertisements
Solution
(i) we know pressure exerted by a liquid column of height h, density p is P = h x px g.
The pressure exerted by a mercury column of height 70 cm.
Density of mercury = 13.6 g/cc = 1.36 x 104kg/m3.
Pmercury = 0.7 x 1.36 x 104 x 9.8 = 9.32 x 104 Nm-2.
Let the height of the water column = hm.
Density of water = 1g/cc = 103 kg/m3.
Pwater = h x 103 x 9.8 = 9.8h x 103 Nm-2,
Now put Pmercury = Pwater
9.8 h x 103 = 9.32 x 104
h = 93.2/9.8 = 9.52 m.
So, 9.52 m height of water column would exert the same pressure on its base as 70 cm column of mercury.
(ii) The height of the water column would not change if the cross-section of the water column is made wider.
APPEARS IN
RELATED QUESTIONS
What is the pressure exerted by 75 cm vertical column of mercury of density 13600 kgm−3 in SI units?
[Take g = 9.8 ms−2].
Pressure at the bottom of the sea at some particular place is 8968960 Pa. If the density of seawater is 1040 kgm3 calculate the depth of the sea. Take g = 9.8 ms−2. Neglect the pressure of the atmosphere.
The pressure of water on the ground floor is 160000 Pa. Calculate the pressure on the fifth floor, at a height of 15 m.
The normal pressure of air is 76 cm of mercury. Calculate the pressure in SI units.
[Density of mercury = 13600 kg/m3 and g = 10 m/s2]
