Advertisements
Advertisements
Question
What is the current in the circuit shown (Fig. )
Advertisements
Solution
Given, potential difference, V = 2 volt
Let R be the equivalent resistance of the circuit and I be the current flowing through it; then
R = `[(1/2 + 1/2)^-1+ (1)]`
R = [1 + 1] = 2 Ω
`therefore "I" = "V"/"R" = 2/2` = 1 A
APPEARS IN
RELATED QUESTIONS
Which particles are responsible for current in conductors?
A 2 kWh heater, a 200 W TV and three 100 W lamps are all switched on from 6 p.m. to 10 p.m. What is the total cost at Rs 5.50 per kWh?
Write the formula for electric power in terms of potential difference and current.
Water in an electric kettle connected to a 220 V supply took 5 minutes to reach its boiling point. How long would it have taken if the supply voltage had fallen to 200 V?
A simple electric circuit has 24 V battery and a resistor of 60 Ω. What will be the current in the circuit? The resistance of the connecting wires is negligible.
An electric kettle is rated 3kW, 250V. What should be the current capacity of the fuse with it?
The equation I2R seems to suggest that the rate of heating in a resistor is reduced if resistance decreases, whereas equation P = V2/R suggests just the opposite. How do you reconcile this problem?
A torch bulb is rated at 3 V and 600 mA. Calculate it’s
- power
- resistance
- energy consumed if it is used for 4 hours.
Electric power is inversely proportional to ____________.
What is the commercial unit of electrical energy?
